Welcome, students! Today, we're going to dive deep into one of the most fundamental and powerful concepts in Linear Algebra: the
Inverse of a Square Matrix. Just like division is the inverse operation of multiplication in arithmetic, matrix inversion plays a similar role in matrix algebra. This concept is absolutely crucial for solving systems of linear equations, understanding transformations, and is a recurring topic in JEE Mains and Advanced.
Let's start our journey!
### 1. The Idea of an Inverse: A Quick Recap
Remember how in the world of numbers, for any non-zero number 'a', there exists a multiplicative inverse, denoted as $a^{-1}$ or $1/a$? This inverse has a special property:
$a cdot a^{-1} = a^{-1} cdot a = 1$.
For example, the inverse of 5 is $1/5$, because $5 cdot (1/5) = 1$. The inverse of $3/4$ is $4/3$, because $(3/4) cdot (4/3) = 1$.
Now, let's extend this idea to matrices. Can we find a matrix that, when multiplied by a given matrix, gives us the matrix equivalent of '1'? Yes, we can! The matrix equivalent of '1' is the
Identity Matrix, denoted by $I$.
### 2. Definition of the Inverse of a Square Matrix
A square matrix $A$ of order $n imes n$ is said to be
invertible if there exists another square matrix $B$ of the same order $n imes n$ such that:
$AB = BA = I$
where $I$ is the identity matrix of order $n$.
If such a matrix $B$ exists, it is called the
inverse of A and is denoted by $A^{-1}$. So, we can write:
$A A^{-1} = A^{-1} A = I$
Important Note: Only
square matrices can have inverses. Why? Because for the products $AB$ and $BA$ to both be defined and result in an identity matrix (which is square), $A$ and $B$ must be square matrices of the same order.
### 3. Condition for Existence: Singular vs. Non-Singular Matrices
Not all square matrices have an inverse. Just like zero doesn't have a multiplicative inverse (you can't divide by zero!), some matrices also don't have an inverse. This brings us to the crucial concept of
determinants.
A square matrix $A$ is classified into two types based on its determinant:
1.
Singular Matrix: A square matrix $A$ is called a
singular matrix if its determinant is zero, i.e., $ ext{det}(A) = 0$.
*
Warning: A singular matrix does not have an inverse. You can think of this as the matrix equivalent of trying to divide by zero. If $ ext{det}(A) = 0$, the formula we're about to derive will involve division by zero, making the inverse undefined.
2.
Non-Singular Matrix: A square matrix $A$ is called a
non-singular matrix if its determinant is non-zero, i.e., $ ext{det}(A)
eq 0$.
*
Good News: A non-singular matrix always has an inverse. This is the fundamental condition for the existence of $A^{-1}$.
### 4. Deriving the Formula for the Inverse (Using Adjoint)
To find the inverse of a non-singular matrix, we use its
adjoint. Recall that the adjoint of a matrix $A$, denoted as $ ext{adj}(A)$, is the transpose of the matrix of cofactors of $A$.
We know a very important property linking a matrix, its adjoint, and its determinant:
$A cdot ( ext{adj} A) = ( ext{adj} A) cdot A = ext{det}(A) cdot I$
Now, let's assume $A$ is a non-singular matrix, so $ ext{det}(A)
eq 0$. We can divide the entire equation by $ ext{det}(A)$:
$A cdot left( frac{1}{ ext{det}(A)} ext{adj} A
ight) = left( frac{1}{ ext{det}(A)} ext{adj} A
ight) cdot A = I$
By comparing this equation with the definition of the inverse ($A A^{-1} = A^{-1} A = I$), we can clearly see that:
$A^{-1} = frac{1}{ ext{det}(A)} ( ext{adj} A)$
This is the central formula for finding the inverse of a square matrix!
Prerequisite Knowledge Check (for JEE): To master inverse calculation, you must be proficient in:
1. Calculating the determinant of a matrix (especially for 2x2 and 3x3 matrices).
2. Finding the cofactors of elements.
3. Forming the cofactor matrix.
4. Calculating the adjoint of a matrix (transpose of the cofactor matrix).
### 5. Step-by-Step Procedure to Find the Inverse
Let's consolidate the steps to find the inverse of a square matrix $A$:
1.
Calculate $ ext{det}(A)$: Find the determinant of the given matrix $A$.
2.
Check for Singularity:
* If $ ext{det}(A) = 0$, then $A^{-1}$ does not exist. Stop here and state that the matrix is singular.
* If $ ext{det}(A)
eq 0$, then $A^{-1}$ exists. Proceed to the next step.
3.
Find the Cofactor Matrix: Calculate the cofactor $C_{ij}$ for each element $a_{ij}$ of matrix $A$. The cofactor $C_{ij} = (-1)^{i+j} M_{ij}$, where $M_{ij}$ is the minor of $a_{ij}$.
4.
Form the Adjoint Matrix: The adjoint of $A$, $ ext{adj}(A)$, is the transpose of the cofactor matrix. That is, if $C = [C_{ij}]$ is the cofactor matrix, then $ ext{adj}(A) = C^T$.
5.
Apply the Formula: Use the formula $A^{-1} = frac{1}{ ext{det}(A)} ( ext{adj} A)$ to find the inverse.
### 6. Illustrative Examples
Let's walk through some examples to solidify our understanding.
#### Example 1: Inverse of a 2x2 Matrix
Find the inverse of the matrix $A = egin{pmatrix} 2 & 3 \ 1 & 4 end{pmatrix}$.
Solution:
1.
Calculate $ ext{det}(A)$:
$ ext{det}(A) = (2 imes 4) - (3 imes 1) = 8 - 3 = 5$.
Since $ ext{det}(A) = 5
eq 0$, $A^{-1}$ exists.
2.
Find the Cofactor Matrix:
* $C_{11} = (-1)^{1+1} (4) = 4$
* $C_{12} = (-1)^{1+2} (1) = -1$
* $C_{21} = (-1)^{2+1} (3) = -3$
* $C_{22} = (-1)^{2+2} (2) = 2$
The cofactor matrix $C = egin{pmatrix} 4 & -1 \ -3 & 2 end{pmatrix}$.
3.
Form the Adjoint Matrix:
$ ext{adj}(A) = C^T = egin{pmatrix} 4 & -3 \ -1 & 2 end{pmatrix}$.
Quick Trick for 2x2: For a matrix $egin{pmatrix} a & b \ c & d end{pmatrix}$, the adjoint is $egin{pmatrix} d & -b \ -c & a end{pmatrix}$. (Swap diagonal elements, change signs of off-diagonal elements). This matches our result!
4.
Apply the Formula:
$A^{-1} = frac{1}{ ext{det}(A)} ( ext{adj} A) = frac{1}{5} egin{pmatrix} 4 & -3 \ -1 & 2 end{pmatrix} = egin{pmatrix} 4/5 & -3/5 \ -1/5 & 2/5 end{pmatrix}$.
#### Example 2: Inverse of a 3x3 Matrix
Find the inverse of the matrix $A = egin{pmatrix} 1 & 2 & 3 \ 0 & 1 & 4 \ 5 & 6 & 0 end{pmatrix}$.
Solution:
1.
Calculate $ ext{det}(A)$:
Using expansion along the first row:
$ ext{det}(A) = 1 cdot ext{det}egin{pmatrix} 1 & 4 \ 6 & 0 end{pmatrix} - 2 cdot ext{det}egin{pmatrix} 0 & 4 \ 5 & 0 end{pmatrix} + 3 cdot ext{det}egin{pmatrix} 0 & 1 \ 5 & 6 end{pmatrix}$
$= 1(0 - 24) - 2(0 - 20) + 3(0 - 5)$
$= -24 - 2(-20) + 3(-5)$
$= -24 + 40 - 15 = 1$.
Since $ ext{det}(A) = 1
eq 0$, $A^{-1}$ exists.
2.
Find the Cofactor Matrix:
* $C_{11} = (1)(0) - (4)(6) = -24$
* $C_{12} = -((0)(0) - (4)(5)) = -(-20) = 20$
* $C_{13} = (0)(6) - (1)(5) = -5$
* $C_{21} = -((2)(0) - (3)(6)) = -(-18) = 18$
* $C_{22} = (1)(0) - (3)(5) = -15$
* $C_{23} = -((1)(6) - (2)(5)) = -(6 - 10) = -(-4) = 4$
* $C_{31} = (2)(4) - (3)(1) = 8 - 3 = 5$
* $C_{32} = -((1)(4) - (3)(0)) = -(4 - 0) = -4$
* $C_{33} = (1)(1) - (2)(0) = 1 - 0 = 1$
The cofactor matrix $C = egin{pmatrix} -24 & 20 & -5 \ 18 & -15 & 4 \ 5 & -4 & 1 end{pmatrix}$.
3.
Form the Adjoint Matrix:
$ ext{adj}(A) = C^T = egin{pmatrix} -24 & 18 & 5 \ 20 & -15 & -4 \ -5 & 4 & 1 end{pmatrix}$.
4.
Apply the Formula:
$A^{-1} = frac{1}{ ext{det}(A)} ( ext{adj} A) = frac{1}{1} egin{pmatrix} -24 & 18 & 5 \ 20 & -15 & -4 \ -5 & 4 & 1 end{pmatrix} = egin{pmatrix} -24 & 18 & 5 \ 20 & -15 & -4 \ -5 & 4 & 1 end{pmatrix}$.
### 7. Properties of Inverse Matrices (JEE Focus!)
Understanding these properties is crucial for solving conceptual problems in JEE.
| Property | Description & Derivation (where applicable)
1. Uniqueness of Inverse |
A square matrix can have only one inverse. If $B$ and $C$ are both inverses of $A$, then $B=C$.
Proof: Assume $AB=BA=I$ and $AC=CA=I$.
Then $B = BI = B(AC) = (BA)C = IC = C$.
Hence, $B=C$. |
2. Inverse of an Inverse |
The inverse of the inverse of a matrix is the matrix itself:
$(A^{-1})^{-1} = A$
Proof: We know $A A^{-1} = I$. Let $B = A^{-1}$. Then $AB=I$. This means $A$ is the inverse of $B$, i.e., $A = B^{-1} = (A^{-1})^{-1}$. |
3. Inverse of a Product (Reversal Law) |
If $A$ and $B$ are invertible matrices of the same order, then their product $AB$ is also invertible, and its inverse is:
$(AB)^{-1} = B^{-1}A^{-1}$
Caution: The order is reversed! This is similar to the transpose of a product: $(AB)^T = B^T A^T$.
Proof: To show $(AB)^{-1} = B^{-1}A^{-1}$, we need to prove that $(AB)(B^{-1}A^{-1}) = I$.
$(AB)(B^{-1}A^{-1}) = A(BB^{-1})A^{-1} = A(I)A^{-1} = A A^{-1} = I$.
Similarly, $(B^{-1}A^{-1})(AB) = B^{-1}(A^{-1}A)B = B^{-1}(I)B = B^{-1}B = I$.
Since both products yield $I$, the formula is proven. |
4. Inverse of a Transpose |
The inverse of the transpose of a matrix is equal to the transpose of its inverse:
$(A^T)^{-1} = (A^{-1})^T$
Proof: We know $A A^{-1} = I$. Taking the transpose of both sides:
$(A A^{-1})^T = I^T$
$(A^{-1})^T A^T = I$
This equation shows that $(A^{-1})^T$ is the inverse of $A^T$. Hence, $(A^T)^{-1} = (A^{-1})^T$. |
5. Inverse of a Scalar Multiple |
If $k$ is a non-zero scalar and $A$ is an invertible matrix, then:
$(kA)^{-1} = frac{1}{k} A^{-1}$
Proof: We need to show that $(kA)(frac{1}{k}A^{-1}) = I$.
$(kA)(frac{1}{k}A^{-1}) = (k cdot frac{1}{k})(A A^{-1}) = 1 cdot I = I$.
Similarly, $(frac{1}{k}A^{-1})(kA) = I$. |
6. Determinant of an Inverse |
The determinant of the inverse of a matrix is the reciprocal of the determinant of the original matrix:
$ ext{det}(A^{-1}) = frac{1}{ ext{det}(A)}$
Proof: We know $A A^{-1} = I$. Taking the determinant of both sides:
$ ext{det}(A A^{-1}) = ext{det}(I)$
Using the property $ ext{det}(AB) = ext{det}(A) ext{det}(B)$:
$ ext{det}(A) cdot ext{det}(A^{-1}) = 1$
Since $ ext{det}(A)
eq 0$ (for $A^{-1}$ to exist), we can divide by $ ext{det}(A)$:
$ ext{det}(A^{-1}) = frac{1}{ ext{det}(A)}$. |
7. If $A$ is Symmetric, $A^{-1}$ is Symmetric |
If $A^T = A$, then $(A^{-1})^T = A^{-1}$.
Proof: We know $(A^{-1})^T = (A^T)^{-1}$. If $A$ is symmetric, $A^T = A$.
So, $(A^{-1})^T = A^{-1}$. Hence $A^{-1}$ is symmetric. |
### 8. Applications and Importance (JEE Perspective)
The inverse of a matrix is not just a theoretical concept; it has profound applications, especially in solving systems of linear equations.
1.
Solving Systems of Linear Equations:
Consider a system of linear equations:
$a_1x + b_1y + c_1z = d_1$
$a_2x + b_2y + c_2z = d_2$
$a_3x + b_3y + c_3z = d_3$
This can be written in matrix form as $AX = B$, where:
$A = egin{pmatrix} a_1 & b_1 & c_1 \ a_2 & b_2 & c_2 \ a_3 & b_3 & c_3 end{pmatrix}$, $X = egin{pmatrix} x \ y \ z end{pmatrix}$, $B = egin{pmatrix} d_1 \ d_2 \ d_3 end{pmatrix}$.
If $A$ is a non-singular matrix (i.e., $ ext{det}(A)
eq 0$), then $A^{-1}$ exists. We can pre-multiply both sides of $AX=B$ by $A^{-1}$:
$A^{-1}(AX) = A^{-1}B$
$(A^{-1}A)X = A^{-1}B$
$IX = A^{-1}B$
$X = A^{-1}B$
This gives us a unique solution for $x, y, z$. This method is called the
Matrix Method for solving linear equations.
JEE Advanced Insight: If $ ext{det}(A)=0$, the system either has no solution (inconsistent) or infinitely many solutions (consistent). The inverse method only works for unique solutions.
2.
Geometric Transformations: Matrix inverses are used to reverse geometric transformations (e.g., if a matrix represents a rotation, its inverse represents a rotation in the opposite direction).
3.
Cryptography: Simple matrix encryption schemes use matrix multiplication to encode messages, and the inverse matrix is used for decoding.
### 9. CBSE vs. JEE Focus
Aspect |
CBSE/State Boards Focus |
IIT JEE Mains & Advanced Focus |
|---|
Calculation |
Primary focus on direct calculation of $A^{-1}$ for 2x2 and 3x3 matrices. Step-by-step method and accuracy are key. |
Calculation of $A^{-1}$ is often a step in a larger problem. Efficiency and accuracy under time pressure are crucial. Sometimes, you don't need to find the full inverse, just a specific element or property. |
Properties |
Understanding basic properties like $(AB)^{-1} = B^{-1}A^{-1}$ and $(A^T)^{-1} = (A^{-1})^T$. Simple proofs are expected. |
In-depth application of all properties, often combined with determinants, adjoint, and other matrix operations. Problems may require proving properties or using them to derive new results. |
Theoretical Depth |
Understanding the definition and the condition $ ext{det}(A)
eq 0$. |
Deeper understanding of why $ ext{det}(A)=0$ leads to no inverse (e.g., relation to linear dependence of rows/columns). Questions involving characteristic equations and Cayley-Hamilton theorem, where $A^{-1}$ can be expressed in terms of $A$. |
Problem Complexity |
Direct questions on finding $A^{-1}$ or solving systems of equations using the matrix method. |
Multi-concept problems: finding $A^{-1}$ of a matrix with variable entries, problems involving inverse of powers of matrices ($A^n$), inverse of block matrices, using inverse in transformation of coordinates, or abstract problems requiring strong conceptual grip. |
Alternative Methods |
Gaussian elimination/row operations for finding inverse (though less emphasized for 3x3 than adjoint method). |
Knowledge of Gaussian elimination for inverse is important for higher dimensions, but for 3x3, adjoint is faster. May encounter problems where one method is more efficient than another. |
### 10. Common Pitfalls and Tips
*
Always check $ ext{det}(A)$ first! If it's zero, save yourself time and state that the inverse doesn't exist.
*
Sign errors in cofactors: This is the most common mistake. Be meticulous with the $(-1)^{i+j}$ term.
*
Transposing for adjoint: Remember, $ ext{adj}(A)$ is the transpose of the cofactor matrix, not the cofactor matrix itself.
*
Scalar multiplication: When you multiply $frac{1}{ ext{det}(A)}$ with $ ext{adj}(A)$, ensure every element of the adjoint matrix is multiplied by the scalar.
*
Verifying your answer: If time permits, you can quickly check your inverse by performing $AA^{-1}$ or $A^{-1}A$. It should result in the identity matrix $I$.
Mastering the inverse of a square matrix is a cornerstone for advanced matrix algebra. Practice extensively with various types of problems, and pay close attention to the properties. This will give you a significant advantage in competitive exams like JEE!