๐References & Further Reading (10)
Book
Introduction to Statistical Mechanics and Thermodynamics
By: Robert P. H. Gasser and W. G. Richards
Provides a more rigorous, university-level approach, detailing how the foundational assumptions lead directly to the Ideal Gas Law and the Maxwell-Boltzmann distribution.
Note: Useful for advanced conceptual clarity regarding the limits of KTG and preparing for JEE Advanced/Olympiad level questions on deviations.
Website
Kinetic Theory of Gases: Assumptions and Derivations
By: Khan Academy
Video and text resources explaining the basic model of an ideal gas and the fundamental postulates (e.g., elastic collisions, negligible volume).
Note: Excellent pedagogical tool for conceptual clarity. Focuses heavily on the qualitative understanding required for board exams.
PDF
Thermal Physics Lecture Notes (Section 2.1: The Assumptions)
By: Dr. S. K. Das
Detailed university lecture notes discussing the limitations of the KTG assumptions, particularly the implications of non-negligible molecular volume and intermolecular forces.
Note: Highly relevant for JEE Advanced preparation, focusing on the connection between the assumptions and the correction factors (a and b) in the real gas equation.
Article
The Ideal Gas Model and Its Failure Points
By: Dr. Elena Petrov
A pedagogical article clearly contrasting the strict assumptions of KTG (ideal gas) versus the realities of real gases, focusing on high pressure and low temperature scenarios.
Note: Directly links the failure of the KTG assumptions to observable physical phenomena, which is a common topic in JEE Main application questions.
Research_Paper
Corrections to the Ideal Gas Law: The Role of Molecular Volume and Interaction
By: M. L. Gupta and V. Sharma
A modern analytical paper focusing on how relaxing the two primary KTG assumptions (negligible volume and zero interaction force) quantitatively modifies the pressure and volume terms, leading to equations of state like Van der Waals.
Note: Directly supports the understanding of the Van der Waals equation derivation which is critical for JEE Advanced thermal physics and chemistry.
โ ๏ธCommon Mistakes to Avoid (63)
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th
โ
Misinterpreting the 'Negligible Intermolecular Force' Assumption
Students often treat the KTG assumption of 'no intermolecular forces (except during collision)' as absolute, leading to errors in conceptual problems related to internal energy and real gas behavior. They fail to understand that this assumption implies the potential energy component (U) associated with interaction is constant (or zero), making the internal energy dependent solely on kinetic energy (temperature).
๐ญ Why This Happens:
This is a minor conceptual slip rooted in confusing the theoretical limit (Ideal Gas) with practical application (Real Gases/Thermodynamics). When asked to analyze the internal energy change or Joule-Thomson expansion, students sometimes forget that $U_{ideal}$ being independent of volume ($V$) is a direct consequence of this assumption.
โ
Correct Approach:
For JEE Advanced, KTG assumptions must be viewed as the foundation for the ideal gas law ($PV=nRT$). The assumption of zero interaction means:
- The internal energy ($U$) of the gas is purely kinetic.
- $U$ is a function of $T$ only (i.e., $U=f(T)$).
- The internal pressure $left(frac{partial U}{partial V}
ight)_T$ is zero.
This assumption breaks down in real gases, where the attractive forces necessitate the inclusion of the van der Waals correction term 'a'.
๐ Examples:
โ Wrong:
Wrong Conceptual Statement: 'An ideal gas expands isothermally and performs work. Since the potential energy must change to provide this work, the internal energy of the ideal gas decreases.' (Incorrect: For ideal gases, $U$ depends only on $T$. Since $T$ is constant, $Delta U=0$. The work done comes from the heat absorbed.)
โ
Correct:
| Concept | KTG Assumption Used |
|---|
| Internal Energy (U) depends only on T. | Negligible intermolecular forces (potential energy is zero/constant). |
| Molecules travel in straight lines. | Negligible intermolecular forces (no long-range steering/curving of path). |
๐ก Prevention Tips:
Always link KTG assumptions to thermodynamic consequences:
- Assumption 1 (Volume): Leads to the 'b' correction term (co-volume) in van der Waals equation.
- Assumption 2 (Forces): Leads to the 'a' correction term (attractive forces) and the concept that $Delta U = 0$ during isothermal expansion.
CBSE_12th