Welcome back, future IITians! Today, we're diving deep into the fascinating world of sulphur and its compounds, specifically focusing on hydrogen sulphide (
H₂S), sulphur dioxide (
SO₂), and the diverse family of its
oxoacids. These compounds are crucial from both theoretical and practical standpoints, frequently appearing in JEE questions due to their unique properties and varied oxidation states.
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1. Hydrogen Sulphide (H₂S): The Rotten Egg Gas
Hydrogen sulphide, commonly known as
rotten egg gas, is a compound of sulphur in its lowest possible oxidation state of
-2. This low oxidation state is key to understanding its primary chemical characteristic: its strong reducing power.
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1.1 Structure of H₂S
H₂S has a bent or V-shaped molecular geometry, similar to water (H₂O). The central sulphur atom undergoes
sp³ hybridization, leading to a tetrahedral electron geometry, but two of these hybrid orbitals are occupied by lone pairs of electrons.
*
Bond Angle: Approximately 92°, which is less than the ideal tetrahedral angle (109.5°) due to the repulsion from the two lone pairs on sulphur.
*
Polarity: H₂S is a polar molecule due to the bent shape and the difference in electronegativity between sulphur and hydrogen.
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1.2 Preparation of H₂S
1.
Laboratory Method: By the action of dilute non-oxidizing acids on metal sulphides.
Example: Reaction of iron(II) sulphide with dilute sulphuric acid.
FeS (s) + H₂SO₄ (aq) → FeSO₄ (aq) + H₂S (g)
ZnS (s) + 2HCl (aq) → ZnCl₂ (aq) + H₂S (g)
2.
Industrial Method:
*
From natural gas: H₂S is a significant component of "sour" natural gas and is removed before distribution.
*
From the reaction of hydrogen with molten sulphur:
H₂ (g) + S (l) → H₂S (g) (at high temperatures)
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1.3 Properties of H₂S
#####
1.3.1 Physical Properties:
*
Colorless gas with a characteristic
rotten egg smell.
* Highly
poisonous, even in low concentrations. Prolonged exposure can lead to paralysis of the olfactory nerves, making its detection by smell unreliable.
* Slightly heavier than air.
* Moderately soluble in water, forming a weak acidic solution called
hydrosulphuric acid.
#####
1.3.2 Chemical Properties:
1.
Acidic Nature:
H₂S is a
weak dibasic acid (can donate two protons). It dissociates in two steps in water:
H₂S (aq) ⇌ H⁺ (aq) + HS⁻ (aq) (Ka1 = 1.0 × 10⁻⁷)
HS⁻ (aq) ⇌ H⁺ (aq) + S²⁻ (aq) (Ka2 = 1.2 × 10⁻¹³)
It reacts with bases to form salts (sulphides or hydrosulphides).
Example:
H₂S + NaOH → NaHS (sodium hydrosulphide) + H₂O
H₂S + 2NaOH → Na₂S (sodium sulphide) + 2H₂O
JEE Tip: The K
a values indicate that H₂S is a very weak acid, much weaker than common mineral acids. Its second dissociation constant (K
a2) is extremely small, meaning S²⁻ ions are present in very low concentrations in aqueous solutions of H₂S.
2.
Strong Reducing Agent:
This is the
most significant chemical property of H₂S. Sulphur in H₂S is in its lowest oxidation state (-2) and can only increase its oxidation state (e.g., to 0 in S, +4 in SO₂, or +6 in H₂SO₄).
Examples:
*
Reaction with Halogens: H₂S reduces halogens to halide ions, getting oxidized to free sulphur.
H₂S (g) + Cl₂ (g) → 2HCl (g) + S (s)
H₂S (g) + Br₂ (aq) → 2HBr (aq) + S (s)
*
Reaction with Sulphur Dioxide (SO₂): An important reaction where both act as redox agents.
2H₂S (g) + SO₂ (g) → 3S (s) + 2H₂O (l)
(Here, S in H₂S goes from -2 to 0, and S in SO₂ goes from +4 to 0).
*
Reaction with Oxidizing Agents: H₂S readily reduces strong oxidizing agents like potassium permanganate (KMnO₄), potassium dichromate (K₂Cr₂O₇), nitric acid (HNO₃), and iron(III) salts.
5H₂S + 2KMnO₄ + 3H₂SO₄ → 5S + 2MnSO₄ + K₂SO₄ + 8H₂O
(Mn goes from +7 to +2, S from -2 to 0)
H₂S + 2FeCl₃ → 2FeCl₂ + S + 2HCl
(Fe goes from +3 to +2, S from -2 to 0)
3.
Combustion:
*
In sufficient oxygen: Burns with a blue flame to form sulphur dioxide and water.
2H₂S (g) + 3O₂ (g) → 2SO₂ (g) + 2H₂O (l)
*
In insufficient oxygen: Forms sulphur and water.
2H₂S (g) + O₂ (g) → 2S (s) + 2H₂O (l)
4.
Precipitation of Metal Sulphides:
H₂S is widely used in
qualitative analysis for the precipitation of metal sulphides. The selective precipitation of various metal ions as their sulphides, depending on the pH of the solution, is a key concept.
Example:
* In acidic medium, only highly insoluble sulphides (e.g., HgS, PbS, CdS, Bi₂S₃, CuS, As₂S₃, Sb₂S₃, SnS₂) precipitate because the concentration of S²⁻ ions is very low.
* In alkaline medium, the S²⁻ concentration is higher, leading to precipitation of less insoluble sulphides (e.g., FeS, NiS, CoS, MnS, ZnS).
Remember: The solubility product (Ksp) and the common ion effect play a crucial role here.
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1.4 Uses of H₂S
* Chiefly used as an analytical reagent in qualitative analysis for the precipitation of metal sulphides.
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2. Sulphur Dioxide (SO₂): The Pungent Gas
Sulphur dioxide is another important oxide of sulphur, where sulphur exhibits a
+4 oxidation state. This intermediate oxidation state allows SO₂ to act as
both an oxidizing and a reducing agent.
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2.1 Structure of SO₂
SO₂ has a
bent or V-shaped geometry. The central sulphur atom is
sp² hybridized. It exhibits
resonance between two equivalent structures:
O=S-O⁻ ↔ ⁻O-S=O
Both S-O bond lengths are identical and intermediate between a single and a double bond. There is one lone pair on the sulphur atom.
*
Bond Angle: Approximately 119.5°.
*
Polarity: SO₂ is a polar molecule.
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2.2 Preparation of SO₂
1.
Laboratory Method:
* By burning sulphur in air:
S (s) + O₂ (g) → SO₂ (g)
* By the action of dilute sulphuric acid on sulphites:
Na₂SO₃ (s) + H₂SO₄ (aq) → Na₂SO₄ (aq) + H₂O (l) + SO₂ (g)
(Or from NaHSO₃ with HCl)
2.
Industrial Method:
*
Roasting of sulphide ores: This is the most common industrial method. Metal sulphides are heated in air to convert them into metal oxides and sulphur dioxide.
4FeS₂ (s) + 11O₂ (g) → 2Fe₂O₃ (s) + 8SO₂ (g)
2ZnS (s) + 3O₂ (g) → 2ZnO (s) + 2SO₂ (g)
*
By-product of power generation: Burning of fossil fuels containing sulphur.
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2.3 Properties of SO₂
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2.3.1 Physical Properties:
*
Colorless gas with a
pungent and suffocating smell.
*
Highly soluble in water.
* Easily liquefiable at room temperature under pressure (boiling point -10°C).
* Heavier than air.
#####
2.3.2 Chemical Properties:
1.
Acidic Nature:
SO₂ is an
acidic oxide. It dissolves in water to form
sulphurous acid (H₂SO₃), a weak dibasic acid. Note that H₂SO₃ is an unstable acid and exists only in aqueous solution.
SO₂ (g) + H₂O (l) ⇌ H₂SO₃ (aq)
Sulphurous acid reacts with bases to form sulphites and bisulphites.
Example:
SO₂ + 2NaOH → Na₂SO₃ (sodium sulphite) + H₂O
SO₂ + NaOH → NaHSO₃ (sodium bisulphite) + H₂O
2.
Reducing Agent:
Since sulphur is in the
+4 oxidation state, it can be oxidized further to +6. This makes SO₂ a strong reducing agent, especially in the presence of water.
Examples:
*
Reaction with Halogens: Reduces halogens to hydrohalic acids, forming sulphuric acid.
SO₂ (g) + Cl₂ (g) + 2H₂O (l) → H₂SO₄ (aq) + 2HCl (aq)
(S goes from +4 to +6, Cl from 0 to -1)
*
Reaction with KMnO₄: Decolorizes acidified potassium permanganate solution (purple to colorless).
5SO₂ + 2KMnO₄ + 2H₂O → K₂SO₄ + 2MnSO₄ + 2H₂SO₄
(Mn goes from +7 to +2, S from +4 to +6)
*
Reaction with K₂Cr₂O₇: Changes acidified potassium dichromate solution from orange to green.
3SO₂ + K₂Cr₂O₇ + H₂SO₄ → K₂SO₄ + Cr₂(SO₄)₃ + H₂O
(Cr goes from +6 to +3, S from +4 to +6)
*
Bleaching Action: SO₂ acts as a temporary bleaching agent for delicate articles like silk, wool, and straw. It bleaches by
reduction (formation of colorless compounds). The bleached color can be restored on exposure to air (oxidation).
Colored substance + SO₂ + H₂O → Reduced colorless product + H₂SO₄
Contrast with Cl₂: Chlorine bleaches by oxidation, which is permanent.
3.
Oxidizing Agent:
Sulphur in SO₂ (+4 oxidation state) can also be reduced to lower oxidation states (0 in S, or -2 in H₂S). Thus, SO₂ also acts as an oxidizing agent, especially with strong reducing agents.
Examples:
*
Reaction with H₂S:
SO₂ (g) + 2H₂S (g) → 3S (s) + 2H₂O (l)
(S in SO₂ goes from +4 to 0, S in H₂S from -2 to 0)
*
Reaction with Magnesium:
2Mg (s) + SO₂ (g) → 2MgO (s) + S (s)
(Mg goes from 0 to +2, S from +4 to 0)
*
Reaction with Carbon:
C (s) + 2SO₂ (g) → CO₂ (g) + 2S (s)
(C goes from 0 to +4, S from +4 to 0)
4.
Addition Reactions:
SO₂ can form addition compounds, e.g., with unsaturated hydrocarbons (in specific conditions) or with sodium sulphite (forming sodium thiosulphate).
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2.4 Uses of SO₂
* Manufacture of
sulphuric acid (Contact Process).
* Bleaching agent for wool, silk, straw, etc.
* Antichlor (removes excess chlorine) and disinfectant.
* Preservative for food (e.g., fruit juices).
* Refrigerant (liquid SO₂).
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3. Oxoacids of Sulphur: A Diverse Family
Sulphur, being a versatile element, forms a large number of oxoacids (acids containing oxygen, hydrogen, and sulphur). The ability of sulphur to exist in various oxidation states (+2, +4, +5, +6) and to form both S-S bonds and S-O-S linkages contributes to this diversity.
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3.1 General Features of Oxoacids of Sulphur
* All oxoacids of sulphur contain at least one
S=O (sulphuryl) group and at least one
S-OH (hydroxyl) group. The hydrogen atom in the S-OH group is acidic.
* Some oxoacids contain S-S linkages (e.g., polythionic acids, dithionic acid), while others contain S-O-S (pyro-series) or S-O-O-H (peroxo-series) linkages.
* The
oxidation state of sulphur is crucial for characterizing these acids.
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3.2 Important Oxoacids of Sulphur (with structures & oxidation states)
Let's explore the key oxoacids, focusing on their structures, which are frequently asked in JEE exams. To determine the oxidation state of sulphur, we generally assign -2 to oxygen and +1 to hydrogen, then balance the charge. If an S-S bond is present, the oxidation state calculation needs careful consideration (divide the total charge contribution equally if the sulphurs are identical, or calculate individually if different).
Name |
Formula |
Oxidation State of S |
Structure (Simplified) |
Key Features / JEE Focus |
|---|
Sulphurous Acid |
H₂SO₃ |
+4 |
O=S(OH)₂ (Exists in solution only) |
Weak dibasic acid. Sulphur is sp³ hybridized. Not isolable. |
Thiosulphuric Acid |
H₂S₂O₃ |
+2 (average) (+6, -2 for the two S atoms respectively) |
(One S is like central S of H2SO4, other S replaces an O) |
Contains an S-S bond. Unstable, disproportionates. Key in photography (hypo). |
Sulphuric Acid |
H₂SO₄ |
+6 |
O₂S(OH)₂ (S has 4 bonds to O: 2=O, 2-OH) |
Strong dibasic acid. The most important oxoacid. Sulphur is sp³ hybridized. |
Pyrosulphuric Acid (Oleum) |
H₂S₂O₇ |
+6 |
(HO)O₂S-O-SO₂OH (Contains an S-O-S linkage) |
Also known as fuming sulphuric acid. Produced by dissolving SO₃ in H₂SO₄. Key intermediate in contact process. |
Peroxomonosulphuric Acid (Caro's Acid) |
H₂SO₅ |
+6 |
HO-O-SO₂OH (Contains one S-O-O-H peroxo linkage) |
Strong oxidizing agent due to the peroxo bond. Sulphur is sp³ hybridized. |
Peroxodisulphuric Acid (Marshall's Acid) |
H₂S₂O₈ |
+6 |
HO₃S-O-O-SO₃H (Contains one S-O-O-S peroxo linkage) |
Very strong oxidizing agent. Used in the synthesis of H₂O₂. Both S atoms are sp³ hybridized. |
Dithionic Acid |
H₂S₂O₆ |
+5 |
HO₃S-SO₃H (Contains an S-S bond) |
S-S bond is directly between the two sulphur atoms. The two S atoms are equivalent, each in +5 oxidation state. |
Polythionic Acids |
H₂SnO₆ (n = 2-6) |
Variable (e.g., in H₂S₄O₆, two terminal S are +5, two central S are 0) |
HO₃S-(S)n-2-SO₃H (Contains a chain of 'n-2' sulphur atoms between two -SO₃H groups) |
Family of acids with variable number of sulphur atoms linked in a chain. The central S atoms are in zero oxidation state. |
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3.3 Drawing Structures and Determining Oxidation States (JEE Focus)
For JEE, being able to draw the structure and assign oxidation states is vital.
Key Rules:
1. Sulphur usually forms four or six bonds.
2. Oxygen usually forms two bonds (S=O or S-O-H).
3. Hydrogen forms one bond (O-H).
4. Each S-OH group contributes one acidic proton.
5.
Oxidation State Calculation:
* Assign O as -2 (unless in a peroxo linkage, where it's -1).
* Assign H as +1.
* Sum the charges and equate to the overall charge of the molecule (0 for neutral molecules).
* For S-S bonds, consider the electron sharing. If two S atoms are bonded, they contribute equally to the bond, so each S-S bond doesn't directly change the individual oxidation state. However, in polythionic acids, the central 'n-2' S atoms are often considered to be in 0 oxidation state, while the terminal S atoms in the -SO₃H groups are in +5.
Example: Let's determine the oxidation state of S in H₂SO₅ (Caro's Acid):
The structure is HO-O-SO₂OH.
* One H is +1.
* The O in the S-OH group is -2.
* The two O atoms double-bonded to S are -2 each.
* The O-O (peroxo) linkage has each O as -1.
Let x be the oxidation state of S.
Equation: (2 * +1 for H) + (1 * -1 for peroxo O) + (1 * -1 for peroxo O) + (1 * -2 for OH O) + (2 * -2 for S=O) + x = 0
2 - 1 - 1 - 2 - 4 + x = 0
x - 6 = 0
x = +6
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3.4 Acidity of Oxoacids
The acidity of oxoacids generally increases with:
1.
Increase in the number of non-hydroxyl oxygen atoms: These oxygen atoms are double-bonded to sulphur (S=O), making sulphur more electronegative, thus pulling electron density from the S-OH bond and making the H more easily dissociable.
Example: H₂SO₄ (two S=O) is a much stronger acid than H₂SO₃ (one S=O).
2.
Increase in the oxidation state of the central atom: A higher positive oxidation state means greater electron-withdrawing capacity, strengthening the acid.
Example: S in H₂SO₄ (+6) vs. S in H₂SO₃ (+4).
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By thoroughly understanding the structure, preparation, and properties of H₂S and SO₂, along with the various oxoacids of sulphur, you'll be well-equipped to tackle the advanced problems in JEE. Pay close attention to the redox reactions of H₂S and SO₂, and master the structural aspects and oxidation state determination for the oxoacids. Good luck!