πŸ“–Topic Explanations

🌐 Overview
Hello students! Welcome to the fascinating world of Intercepts of a line on coordinate axes! Understanding these fundamental concepts is like learning the alphabet before you can write a compelling story in mathematics.

Every straight line, when drawn on a coordinate plane, interacts with the two main axes: the X-axis and the Y-axis. Imagine a train track (our line) crossing two main roads that run perpendicular to each other – one east-west (X-axis) and one north-south (Y-axis). The points where the track crosses these roads are exactly what we call intercepts!



In this section, we're going to demystify these crucial points. The point where a line crosses the X-axis is called the X-intercept, and similarly, where it crosses the Y-axis is the Y-intercept. These seemingly simple points hold immense power in understanding the behavior and position of a line.



Why are these intercepts so important? Well, they are the cornerstones of coordinate geometry. Knowing the intercepts allows you to:



  • Quickly sketch the graph of any linear equation.

  • Determine the general orientation of a line.

  • Solve a variety of problems in JEE Main and board exams, especially those involving areas of triangles formed by lines and coordinate axes, or finding specific points that define geometric figures.

  • Formulate the special "intercept form" of a linear equation, which simplifies many calculations.



Throughout this module, you will learn to identify, calculate, and utilize these intercepts from different forms of linear equations. You'll discover how they act as critical reference points, giving you immediate insights into a line's position without needing to plot multiple points.



Get ready to explore these fundamental concepts that will not only boost your problem-solving skills but also lay a strong foundation for more advanced topics in geometry and calculus. Let's embark on this exciting journey to master the intercepts of a line!

πŸ“š Fundamentals
Hello everyone! Welcome to our journey into the fascinating world of Coordinate Geometry. Today, we're going to start with a very fundamental, yet super important, concept: "Intercepts of a line on the coordinate axes."

Don't let the fancy name scare you! It's actually a very intuitive idea, and understanding it will make sketching lines much easier and faster. Think of it like this: if a road (our line) crosses two major highways (the X-axis and Y-axis), where does it cross them? Those crossing points are essentially what we call 'intercepts'.

Let's break it down!

1. What are Coordinate Axes? (A Quick Recap)


Before we talk about intercepts, let's quickly remember our coordinate system. We have two perpendicular lines:

  • The horizontal line is called the X-axis. Every point on this axis has a y-coordinate of 0.

  • The vertical line is called the Y-axis. Every point on this axis has an x-coordinate of 0.

  • The point where they meet is called the origin, denoted as (0, 0).


Any point in this plane can be uniquely identified by its coordinates (x, y).

2. The X-Intercept: Where the Line Meets the X-Axis



Imagine drawing any straight line on your graph paper. Unless it's parallel to the X-axis, it's bound to cross the X-axis at some point. This point of intersection is super special!

Definition: The X-intercept of a line is the point where the line crosses or "intercepts" the X-axis.



Since this point lies *on* the X-axis, what do we know about its y-coordinate? Yes, you guessed it! For any point on the X-axis, its y-coordinate is always zero (y=0).

So, if a line crosses the X-axis at a point (a, 0), then 'a' is what we call the X-intercept value. Sometimes, we simply refer to 'a' as the X-intercept.

How to find the X-intercept:


It's straightforward! If you have the equation of a line, just substitute y = 0 into the equation and solve for x. The value of x you get will be the X-intercept.


Example 1: Finding the X-intercept

Let's find the X-intercept of the line given by the equation: 2x + 3y = 12

  1. To find the X-intercept, we set y = 0.

  2. Substitute y=0 into the equation:

    2x + 3(0) = 12

  3. Simplify:

    2x + 0 = 12

    2x = 12

  4. Solve for x:

    x = 12 / 2

    x = 6


So, the X-intercept of the line 2x + 3y = 12 is 6. This means the line crosses the X-axis at the point (6, 0).


3. The Y-Intercept: Where the Line Meets the Y-Axis



Just like the X-axis, a line (unless parallel to the Y-axis) will also cross the Y-axis at some point.

Definition: The Y-intercept of a line is the point where the line crosses or "intercepts" the Y-axis.



What do we know about any point that lies *on* the Y-axis? Its x-coordinate is always zero (x=0).

So, if a line crosses the Y-axis at a point (0, b), then 'b' is what we call the Y-intercept value. Often, we just refer to 'b' as the Y-intercept.

How to find the Y-intercept:


Similar to the X-intercept, if you have the equation of a line, just substitute x = 0 into the equation and solve for y. The value of y you get will be the Y-intercept.


Example 2: Finding the Y-intercept

Let's find the Y-intercept of the same line: 2x + 3y = 12

  1. To find the Y-intercept, we set x = 0.

  2. Substitute x=0 into the equation:

    2(0) + 3y = 12

  3. Simplify:

    0 + 3y = 12

    3y = 12

  4. Solve for y:

    y = 12 / 3

    y = 4


So, the Y-intercept of the line 2x + 3y = 12 is 4. This means the line crosses the Y-axis at the point (0, 4).


From these two examples, we can quickly sketch the line 2x + 3y = 12 by just plotting the points (6,0) and (0,4) and drawing a straight line through them! See how powerful this concept is for visualization?

4. Why are Intercepts So Important?



  1. Quick Sketching: As we just saw, knowing the X and Y intercepts gives you two specific points on the line. Since two points are enough to define a unique straight line, you can quickly draw the graph of any linear equation. This is extremely useful in exams when you need to visualize things quickly.

  2. Understanding Behavior: Intercepts tell us where the line interacts with the fundamental framework of our coordinate system. They provide critical information about the line's position.

  3. Problem Solving: Many problems in coordinate geometry, especially those involving areas of triangles formed by lines and axes, or finding specific points, often rely on knowing the intercepts.



5. Special Cases & Observations



Let's look at a few interesting scenarios:



  • Line passing through the origin:
    If a line passes through the origin (0,0), then both its X-intercept and Y-intercept will be 0.



    Example: Consider the line y = 2x.

    To find X-intercept: Set y=0 => 0 = 2x => x=0. Point: (0,0).

    To find Y-intercept: Set x=0 => y = 2(0) => y=0. Point: (0,0).

    Both intercepts are 0.



  • Line parallel to the X-axis:
    A horizontal line (equation of the form y = k, where k is a constant) will never cross the X-axis unless k=0 (i.e., it *is* the X-axis).
    So, if k ≠ 0, a line like y = 5 has no X-intercept. It will, however, have a Y-intercept at (0, k).



    Example: Consider the line y = -3.

    To find X-intercept: Set y=0 => 0 = -3. This is impossible! So, no X-intercept.

    To find Y-intercept: Set x=0 => y = -3. Point: (0,-3).




  • Line parallel to the Y-axis:
    A vertical line (equation of the form x = k, where k is a constant) will never cross the Y-axis unless k=0 (i.e., it *is* the Y-axis).
    So, if k ≠ 0, a line like x = 4 has no Y-intercept. It will, however, have an X-intercept at (k, 0).



    Example: Consider the line x = 5.

    To find X-intercept: Set y=0 => x=5. Point: (5,0).

    To find Y-intercept: Set x=0 => 0 = 5. This is impossible! So, no Y-intercept.





6. Intercepts from Different Forms of Linear Equations



Let's see how easily we can spot or derive intercepts from common forms of a linear equation.



  1. General Form: Ax + By + C = 0
    This is the most common form.

    • X-intercept: Set y=0. Ax + B(0) + C = 0 => Ax = -C => x = -C/A (provided A ≠ 0).

    • Y-intercept: Set x=0. A(0) + By + C = 0 => By = -C => y = -C/B (provided B ≠ 0).



    Example 3: Find the intercepts of the line 5x - 2y + 10 = 0.

    Here, A=5, B=-2, C=10.

    X-intercept: x = -C/A = -10/5 = -2. (Point: (-2, 0))

    Y-intercept: y = -C/B = -10/(-2) = 5. (Point: (0, 5))



  2. Slope-Intercept Form: y = mx + c
    This form is very convenient!

    • X-intercept: Set y=0. 0 = mx + c => mx = -c => x = -c/m (provided m ≠ 0).

    • Y-intercept: Set x=0. y = m(0) + c => y = c. That's right! The 'c' in y = mx + c directly represents the Y-intercept! This is why it's called the slope-intercept form.



    Example 4: Find the intercepts of the line y = 3x - 6.

    Here, m=3, c=-6.

    Y-intercept: Directly from the form, it's -6. (Point: (0, -6))

    X-intercept: x = -c/m = -(-6)/3 = 6/3 = 2. (Point: (2, 0))



  3. Intercept Form: x/a + y/b = 1
    This form is explicitly designed to show the intercepts!

    • X-intercept: Set y=0. x/a + 0/b = 1 => x/a = 1 => x = a.

    • Y-intercept: Set x=0. 0/a + y/b = 1 => y/b = 1 => y = b.


    So, in this form, 'a' is the X-intercept, and 'b' is the Y-intercept. This is incredibly useful!

    Example 5: What are the intercepts of the line x/3 + y/(-5) = 1?

    By direct comparison with x/a + y/b = 1, we can see:

    X-intercept: a = 3. (Point: (3, 0))

    Y-intercept: b = -5. (Point: (0, -5))

    Isn't that quick?




JEE/CBSE Focus: While understanding intercepts is fundamental for both CBSE and JEE, in JEE you'll often encounter problems where intercepts are used to form triangles (e.g., finding the area of the triangle formed by a line and the coordinate axes) or to define specific properties of a family of lines. Being quick and accurate in finding intercepts is a must!



Summary Table


Here's a quick reference for finding intercepts:


























Line Equation Form How to find X-intercept How to find Y-intercept
General Form:
Ax + By + C = 0
Set y = 0, solve for x:
x = -C/A
Set x = 0, solve for y:
y = -C/B
Slope-Intercept Form:
y = mx + c
Set y = 0, solve for x:
x = -c/m
Directly the constant:
y = c
Intercept Form:
x/a + y/b = 1
Directly 'a':
x = a
Directly 'b':
y = b


By now, you should have a very solid understanding of what intercepts are and how to find them from any linear equation. This is a crucial building block for many advanced topics in coordinate geometry, so make sure you practice these concepts well! Keep these fundamentals clear, and you'll navigate more complex problems with ease.
πŸ”¬ Deep Dive
Welcome, future engineers, to a deep dive into one of the fundamental concepts of Coordinate Geometry: Intercepts of a Line on Coordinate Axes. This concept might seem simple on the surface, but understanding its nuances is crucial for tackling more complex problems in lines, conic sections, and even 3D geometry.

Let's begin our exploration!

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1. What are Intercepts? - The Basics



Imagine a straight line extending infinitely in both directions. Now, picture our familiar Cartesian coordinate system with its X-axis and Y-axis. When this line crosses or "cuts" these axes, the points where it does so are called its intercept points. The directed distances from the origin to these intercept points are simply called the intercepts.

These intercepts provide vital information about the line's position relative to the coordinate axes and are frequently used in various mathematical problems.

1.1. The X-intercept



The X-intercept of a line is the point where the line crosses the X-axis.

* Key Property: Any point on the X-axis has its Y-coordinate equal to zero. Therefore, the X-intercept point will always be of the form (x, 0).
* How to find it: To find the X-intercept of a line given its equation, simply substitute y = 0 into the equation and solve for x.
* Geometric Interpretation: It tells us how far the line is from the Y-axis when it crosses the X-axis.

1.2. The Y-intercept



The Y-intercept of a line is the point where the line crosses the Y-axis.

* Key Property: Any point on the Y-axis has its X-coordinate equal to zero. Therefore, the Y-intercept point will always be of the form (0, y).
* How to find it: To find the Y-intercept of a line given its equation, simply substitute x = 0 into the equation and solve for y.
* Geometric Interpretation: It tells us how far the line is from the X-axis when it crosses the Y-axis.

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2. Finding Intercepts from Different Forms of a Line's Equation



Let's explore how to determine the intercepts depending on the form in which the line's equation is given.

2.1. General Form of a Straight Line: Ax + By + C = 0



This is the most common and versatile form. Let the equation of a line be Ax + By + C = 0, where A, B, and C are real numbers, and A and B are not both zero.

* To find the X-intercept:
Set y = 0:
Ax + B(0) + C = 0
Ax + C = 0
Ax = -C
x = -C/A (provided A β‰  0)
So, the X-intercept point is (-C/A, 0).
* To find the Y-intercept:
Set x = 0:
A(0) + By + C = 0
By + C = 0
By = -C
y = -C/B (provided B β‰  0)
So, the Y-intercept point is (0, -C/B).


Example 1: Find the intercepts of the line 3x - 4y + 12 = 0.


Step-by-step solution:

  1. For X-intercept: Set y = 0.
    3x - 4(0) + 12 = 0
    3x + 12 = 0
    3x = -12
    x = -4
    The X-intercept point is (-4, 0).

  2. For Y-intercept: Set x = 0.
    3(0) - 4y + 12 = 0
    -4y + 12 = 0
    -4y = -12
    y = 3
    The Y-intercept point is (0, 3).




2.2. Slope-Intercept Form: y = mx + c



This form explicitly gives us the Y-intercept!

* Here, m is the slope of the line, and c is the Y-intercept.
So, the Y-intercept point is directly (0, c).
* To find the X-intercept:
Set y = 0:
0 = mx + c
mx = -c
x = -c/m (provided m β‰  0)
So, the X-intercept point is (-c/m, 0).


Example 2: Find the intercepts of the line y = 2x + 5.


Step-by-step solution:

  1. Y-intercept: From the form y = mx + c, we can directly see that c = 5.
    So, the Y-intercept point is (0, 5).

  2. X-intercept: Set y = 0.
    0 = 2x + 5
    2x = -5
    x = -5/2
    The X-intercept point is (-5/2, 0).




2.3. Intercept Form of a Straight Line: x/a + y/b = 1



This form is explicitly designed to show the intercepts, and it's incredibly useful, especially for JEE problems.

Let the equation of a line be x/a + y/b = 1.

* To find the X-intercept:
Set y = 0:
x/a + 0/b = 1
x/a = 1
x = a
So, the X-intercept point is (a, 0). Here, 'a' is the length of the X-intercept (from origin).
* To find the Y-intercept:
Set x = 0:
0/a + y/b = 1
y/b = 1
y = b
So, the Y-intercept point is (0, b). Here, 'b' is the length of the Y-intercept (from origin).

This is why it's called the intercept form! It directly provides the intercepts.


Derivation: General Form to Intercept Form
Let the general equation of a line be Ax + By + C = 0.
Assuming C β‰  0 (otherwise, the line passes through the origin, and the intercepts are (0,0)), we can rearrange it:
Ax + By = -C
Divide the entire equation by -C (assuming -C β‰  0):
Ax/(-C) + By/(-C) = (-C)/(-C)
x/(-C/A) + y/(-C/B) = 1
Comparing this with x/a + y/b = 1, we get:
a = -C/A (X-intercept)
b = -C/B (Y-intercept)
This confirms our formulas derived from the general form.



Example 3: Convert the line 3x - 4y = 12 into intercept form and find its intercepts.


Step-by-step solution:

  1. The RHS must be 1. So, divide the entire equation by 12:
    (3x)/12 - (4y)/12 = 12/12
    x/4 - y/3 = 1
    To match the standard form x/a + y/b = 1, we write it as:
    x/4 + y/(-3) = 1

  2. Comparing with x/a + y/b = 1:
    a = 4
    b = -3

  3. So, the X-intercept point is (4, 0) and the Y-intercept point is (0, -3).




2.4. Other Forms (Point-Slope, Two-Point, Normal Form)



For other forms, the easiest way to find intercepts is usually to convert them to the general form (Ax + By + C = 0) or the slope-intercept form (y = mx + c) first, and then apply the methods discussed above.

* Point-Slope Form: y - y1 = m(x - x1)
Rearrange to y = mx - mx1 + y1 (Slope-intercept form where c = y1 - mx1).
Alternatively, expand to mx - y + (y1 - mx1) = 0 (General form).
* Two-Point Form: (y - y1) / (y2 - y1) = (x - x1) / (x2 - x1)
Cross-multiply and rearrange to the general form.

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3. Special Cases and JEE-level Considerations



Understanding these special scenarios is crucial for JEE.

3.1. Lines Passing Through the Origin



If a line passes through the origin (0,0), its equation will be of the form y = mx or Ax + By = 0 (i.e., C = 0 in general form).
In this case:
* Setting y = 0 gives mx = 0 => x = 0. So, X-intercept is (0, 0).
* Setting x = 0 gives y = 0. So, Y-intercept is (0, 0).
Both intercepts are at the origin. The "intercept form" x/a + y/b = 1 cannot represent lines passing through the origin because it would imply a=0 and b=0, leading to division by zero.

3.2. Lines Parallel to the Coordinate Axes



* Line Parallel to the X-axis: Equation is y = k (where k is a constant).
* X-intercept: Setting y = 0 gives k = 0.
* If k = 0, the line is the X-axis itself, and it has infinitely many X-intercepts.
* If k β‰  0, there is no X-intercept (the line never crosses the X-axis).
* Y-intercept: Setting x = 0 gives y = k. So, the Y-intercept point is (0, k).

* Line Parallel to the Y-axis: Equation is x = k (where k is a constant).
* X-intercept: Setting y = 0 gives x = k. So, the X-intercept point is (k, 0).
* Y-intercept: Setting x = 0 gives k = 0.
* If k = 0, the line is the Y-axis itself, and it has infinitely many Y-intercepts.
* If k β‰  0, there is no Y-intercept (the line never crosses the Y-axis).

3.3. Length of Intercept vs. Intercept Coordinate



In problems, when "X-intercept" or "Y-intercept" is mentioned, it typically refers to the coordinate value (e.g., 'a' for X-intercept or 'b' for Y-intercept in x/a + y/b = 1). However, sometimes questions might ask for the "length of the intercept cut off by the axes". In such cases, they refer to the positive magnitude of 'a' and 'b', i.e., |a| and |b| respectively. This is important for clarity.

3.4. Area of Triangle Formed by a Line and the Coordinate Axes



This is a frequently tested concept in JEE.
Consider a line in intercept form: x/a + y/b = 1.
It intersects the X-axis at A(a, 0) and the Y-axis at B(0, b). The origin is O(0, 0).
These three points form a right-angled triangle OAB, with the right angle at the origin.
The base of this triangle can be considered as the length along the X-axis, which is |a|.
The height of this triangle can be considered as the length along the Y-axis, which is |b|.

Therefore, the Area of Ξ”OAB = (1/2) Γ— base Γ— height = (1/2) Γ— |a| Γ— |b|.


Example 4 (JEE Focus): A line passes through the point (2, 3) and forms a triangle of area 12 square units with the coordinate axes. Find the equation of the line.


Step-by-step solution:

  1. Let the equation of the line in intercept form be x/a + y/b = 1.
    Here, 'a' is the X-intercept and 'b' is the Y-intercept.

  2. The line passes through (2, 3). So, substitute x=2 and y=3 into the equation:
    2/a + 3/b = 1 --- (1)

  3. The area of the triangle formed with the coordinate axes is 12 sq units.
    So, (1/2) |a| |b| = 12
    This implies |ab| = 24.
    Thus, ab = 24 or ab = -24.

  4. From (1), multiply by ab to clear denominators:
    2b + 3a = ab

  5. Case 1: ab = 24 (This means 'a' and 'b' have the same sign. Since (2,3) is in the first quadrant, both 'a' and 'b' must be positive for the triangle to enclose the point in the first quadrant, though not strictly required.)
    Substitute ab = 24 into 2b + 3a = ab:
    2b + 3a = 24
    From ab = 24, we have b = 24/a. Substitute this into 2b + 3a = 24:
    2(24/a) + 3a = 24
    48/a + 3a = 24
    Multiply by a:
    48 + 3aΒ² = 24a
    3aΒ² - 24a + 48 = 0
    Divide by 3:
    aΒ² - 8a + 16 = 0
    (a - 4)Β² = 0
    So, a = 4.
    If a = 4, then b = 24/4 = 6.
    The equation of the line is x/4 + y/6 = 1.
    Multiply by 12: 3x + 2y = 12.

  6. Case 2: ab = -24 (This means 'a' and 'b' have opposite signs)
    Substitute ab = -24 into 2b + 3a = ab:
    2b + 3a = -24
    From ab = -24, we have b = -24/a. Substitute this into 2b + 3a = -24:
    2(-24/a) + 3a = -24
    -48/a + 3a = -24
    Multiply by a:
    -48 + 3aΒ² = -24a
    3aΒ² + 24a - 48 = 0
    Divide by 3:
    aΒ² + 8a - 16 = 0
    Use the quadratic formula a = [-b Β± sqrt(bΒ² - 4ac)] / 2a:
    a = [-8 Β± sqrt(8Β² - 4(1)(-16))] / 2(1)
    a = [-8 Β± sqrt(64 + 64)] / 2
    a = [-8 Β± sqrt(128)] / 2
    a = [-8 ± 8√2] / 2
    a = -4 ± 4√2
    If a = -4 + 4√2, then b = -24 / (-4 + 4√2) = -6 / (-1 + √2) = 6 / (1 - √2) = 6(1 + √2) / (1 - 2) = -6(1 + √2).
    Equation: x/(-4 + 4√2) + y/(-6(1 + √2)) = 1
    If a = -4 - 4√2, then b = -24 / (-4 - 4√2) = 6 / (1 + √2) = 6(√2 - 1) / (2 - 1) = 6(√2 - 1).
    Equation: x/(-4 - 4√2) + y/(6(√2 - 1)) = 1

  7. Final Answer: There are three possible lines. The simplest one is 3x + 2y = 12. The other two are x/(-4 + 4√2) + y/(-6(1 + √2)) = 1 and x/(-4 - 4√2) + y/(6(√2 - 1)) = 1.




This example demonstrates how different forms of equations and conceptual understanding of intercepts are combined in JEE-level problems. Pay special attention to the possibility of multiple solutions and handling the signs of intercepts for area calculations.

By mastering the concept of intercepts and their applications, you'll build a strong foundation for many advanced topics in coordinate geometry!
🎯 Shortcuts

Mnemonics and Short-Cuts: Intercepts of a Line on Coordinate Axes



Understanding and quickly recalling how to find intercepts and the intercept form of a line is crucial for coordinate geometry problems. Here are some effective mnemonics and short-cuts to aid your memory:

1. Mnemonic for Finding Intercepts: "Z for Zero"


This simple rule helps you remember which coordinate to set to zero when finding an intercept.

*  To find the X-intercept: Set Y = 0
* Mnemonic: "X-intercept is when Y is *Zero*." (X, 0)
* *Think:* Where the line cuts the X-axis, its height (Y-coordinate) must be zero.
*  To find the Y-intercept: Set X = 0
* Mnemonic: "Y-intercept is when X is *Zero*." (0, Y)
* *Think:* Where the line cuts the Y-axis, its horizontal distance from the Y-axis (X-coordinate) must be zero.

This applies to any form of the line's equation (e.g., `Ax + By + C = 0` or `y = mx + c`).

2. Mnemonic for the Intercept Form of a Line: "A under X, B under Y, Equals One, That's the Way!"


The intercept form of a line is:

x/a + y/b = 1


where 'a' is the x-intercept and 'b' is the y-intercept.

*  Mnemonic Phrase: "X over A, Y over B, equals One, for the Intercept Form's decree!"
*  Key Associations:
* 'a' is always the x-intercept (value where the line cuts the x-axis).
* 'b' is always the y-intercept (value where the line cuts the y-axis).
* The sum of the two fractions *must* equal 1. This is a common point of error where students might write 0 or another number.

3. Short-Cut for Converting General Form to Intercept Form:


Given a general linear equation `Ax + By + C = 0`, you can quickly convert it to intercept form:

1. Move the constant term to the right side: `Ax + By = -C`
2. Divide the entire equation by `-C` (assuming `C β‰  0`) to make the right side 1:
`(Ax)/(-C) + (By)/(-C) = 1`
3. Rearrange to match the `x/a + y/b = 1` format:
`x/(-C/A) + y/(-C/B) = 1`
4. Now, you can directly identify:
* x-intercept (a) = -C/A
* y-intercept (b) = -C/B

This short-cut is extremely useful in JEE and board exams for quickly finding intercepts without going through `y=0` or `x=0` steps if the equation is in general form.

Example: For the line `3x + 4y - 12 = 0`
* `3x + 4y = 12`
* `3x/12 + 4y/12 = 1`
* `x/4 + y/3 = 1`
* x-intercept = 4, y-intercept = 3.
* Using the short-cut: `a = -(-12)/3 = 12/3 = 4`, `b = -(-12)/4 = 12/4 = 3`. Matches perfectly!

CBSE vs. JEE Relevance:


*  For CBSE, knowing how to find intercepts and applying the intercept form are direct questions.
*  For JEE Main, these concepts are foundational and are often embedded within more complex problems, such as finding the area of a triangle formed by a line and the axes, or properties of families of lines. Quick and accurate recall via these mnemonics can save valuable time.

Master these simple memory aids to ensure you can swiftly handle questions involving intercepts of a line.
πŸ’‘ Quick Tips

Quick Tips: Intercepts of a Line on Coordinate Axes



Understanding and quickly finding the intercepts of a line is fundamental in coordinate geometry. These quick tips will help you master this concept for both board exams and JEE Main.



  • Definition Recap:

    • The x-intercept is the x-coordinate of the point where the line crosses the x-axis. At this point, the y-coordinate is always zero.

    • The y-intercept is the y-coordinate of the point where the line crosses the y-axis. At this point, the x-coordinate is always zero.




  • How to Find Intercepts from a General Equation (Ax + By + C = 0):

    • To find the x-intercept: Set y = 0 in the equation and solve for x.

      Example: For 2x + 3y - 6 = 0, set y=0 → 2x - 6 = 0 → x = 3. So, x-intercept is 3.

    • To find the y-intercept: Set x = 0 in the equation and solve for y.

      Example: For 2x + 3y - 6 = 0, set x=0 → 3y - 6 = 0 → y = 2. So, y-intercept is 2.




  • The Intercept Form of a Line:

    The equation of a line having x-intercept 'a' and y-intercept 'b' is given by:


    $$ frac{x}{a} + frac{y}{b} = 1 $$


    Tip: If you need to find intercepts, try to convert the given line equation into this form. Once in this form, 'a' directly gives the x-intercept and 'b' gives the y-intercept.


    Example: Convert 2x + 3y - 6 = 0 to intercept form.

    2x + 3y = 6

    Divide by 6: $$frac{2x}{6} + frac{3y}{6} = frac{6}{6}$$

    $$frac{x}{3} + frac{y}{2} = 1$$

    Here, x-intercept (a) = 3 and y-intercept (b) = 2.




  • Special Cases:

    • Line Passing Through the Origin (C = 0 in Ax + By + C = 0): If the constant term is zero, the line passes through the origin (0,0). In this case, both the x-intercept and y-intercept are 0. The intercept form is not applicable here as 'a' and 'b' would be zero, leading to division by zero.

    • Line Parallel to the X-axis (y = k): This line has no x-intercept unless k=0 (in which case it's the x-axis itself). Its y-intercept is k.

    • Line Parallel to the Y-axis (x = k): This line has no y-intercept unless k=0 (in which case it's the y-axis itself). Its x-intercept is k.




  • JEE Main & CBSE Relevance:

    • Intercepts are crucial for finding the area of a triangle formed by a line and the coordinate axes. If the x-intercept is 'a' and y-intercept is 'b', the vertices of the triangle are (0,0), (a,0), and (0,b). The area is $$frac{1}{2} |a cdot b|$$.

    • Used extensively in questions involving properties of straight lines, such as perpendiculars from origin to a line, locus problems, etc.

    • Understanding intercepts helps in quick sketching of lines, which is useful for visualizing problems.





Keep these tips in mind to quickly and accurately handle problems involving intercepts. Practice converting general equations to intercept form to boost your speed!

🧠 Intuitive Understanding

Intuitive Understanding: Intercepts of a Line on Coordinate Axes



Imagine the coordinate plane as a vast grid. When a straight line is drawn on this grid, it often 'cuts' or 'intercepts' the X-axis and the Y-axis at certain points. These points are what we call the intercepts. Understanding them intuitively is crucial for visualizing lines and solving problems in coordinate geometry.



1. The X-Intercept: Where the Line Crosses the X-Axis



  • What it is: The X-intercept is the point where the line crosses or touches the X-axis.

  • Key characteristic: Any point lying on the X-axis always has its Y-coordinate equal to zero. So, the X-intercept is always of the form (x, 0).

  • Intuition: Think of it as the 'horizontal starting point' or where the line 'hits the ground' (the X-axis). You're only interested in how far left or right it is, not how far up or down.



2. The Y-Intercept: Where the Line Crosses the Y-Axis



  • What it is: The Y-intercept is the point where the line crosses or touches the Y-axis.

  • Key characteristic: Any point lying on the Y-axis always has its X-coordinate equal to zero. Therefore, the Y-intercept is always of the form (0, y).

  • Intuition: This is the 'vertical starting point' or where the line 'climbs up or down the wall' (the Y-axis). You're only concerned with how far up or down it is, not how far left or right.



Why are Intercepts Important?



  • Easy Graphing: Knowing the X and Y-intercepts provides two distinct points that lie on the line. Connecting these two points is often the quickest way to draw a straight line.

  • Understanding Position: Intercepts tell us exactly where a line is positioned relative to the origin (0,0). They give a clear picture of how the line slices through the coordinate system.

  • Foundation for JEE/CBSE Problems: Intercepts are fundamental in various problems, including finding the equation of a line (e.g., intercept form of a line: x/a + y/b = 1, where 'a' is the x-intercept and 'b' is the y-intercept), calculating areas of triangles formed by lines and axes, or analyzing geometric properties.



Finding Intercepts from an Equation:


The intuitive understanding directly translates into practical calculation:



  • To find the X-intercept, simply set y = 0 in the line's equation and solve for x.

  • To find the Y-intercept, simply set x = 0 in the line's equation and solve for y.




Example: For the line 2x + 3y = 6

  • To find X-intercept: Set y=0
    2x + 3(0) = 6 ⇒ 2x = 6 ⇒ x = 3. So, X-intercept is (3, 0).

  • To find Y-intercept: Set x=0
    2(0) + 3y = 6 ⇒ 3y = 6 ⇒ y = 2. So, Y-intercept is (0, 2).


You can visualize this line passing through (3,0) on the X-axis and (0,2) on the Y-axis.


Mastering intercepts provides a strong visual and conceptual base for tackling more complex coordinate geometry problems. Keep practicing!


🌍 Real World Applications
The concept of intercepts of a line on coordinate axes is fundamental to understanding linear relationships in various real-world scenarios. These intercepts often represent crucial starting points, limits, or specific conditions within a given model. By identifying where a line crosses the x-axis (x-intercept) or y-axis (y-intercept), we gain valuable insights into the behavior of the system being modeled.

Here are some real-world applications where intercepts play a significant role:



  • Economics and Business:


    • Break-Even Analysis: In a cost-revenue graph, the x-intercept of the cost function might represent the fixed costs (when production is zero). The point where the revenue line intersects the cost line (which is not an intercept in itself but relies on understanding where each line starts) helps determine the break-even point. More directly, if a profit function `P(x)` is plotted, its x-intercepts would indicate the quantity `x` at which profit is zero (break-even points).


    • Fixed Costs/Initial Investment: When modeling total cost `C` as a function of quantity produced `q` (e.g., `C = mq + b`), the y-intercept `b` represents the fixed costs incurred even if no units are produced.


    • Demand/Supply Curves: While often more complex, linear approximations of demand or supply can have intercepts indicating the maximum price consumers would pay for zero quantity demanded, or the minimum price at which producers would supply zero quantity.




  • Physics and Engineering:


    • Motion (Distance-Time Graphs): For an object moving with constant velocity, its position-time graph is a straight line. The y-intercept represents the initial position of the object (at time `t=0`). If the line crosses the x-axis, the x-intercept would indicate the time when the object reaches a position of zero (e.g., the origin).


    • Fluid Dynamics: Modeling the flow rate of a liquid over time, the y-intercept might represent the initial flow rate.




  • Finance:


    • Linear Depreciation: The value of an asset often depreciates linearly over time. A linear model `V = mt + c` (where `V` is value, `t` is time) will have `c` as the y-intercept, representing the initial purchase value of the asset. The x-intercept would represent the time when the asset's value theoretically becomes zero (or reaches its salvage value, if `V` is adjusted).


    • Simple Interest: While the primary focus is on `A = P(1+rt)`, if we plot `Interest (I)` vs `Time (t)` for a fixed principal and rate, the y-intercept is usually zero, indicating no interest at time zero.




  • Environmental Science:


    • Pollution Levels: Modeling the decrease of a pollutant over time, the y-intercept would represent the initial concentration of the pollutant. The x-intercept would indicate the time taken for the pollutant level to reach zero (or a safe threshold).








Illustrative Example: Linear Depreciation


Consider a company that purchases a machine for manufacturing. The machine's value is expected to depreciate linearly over its useful life.
Let `V` be the value of the machine in dollars and `t` be the time in years since purchase.
A linear depreciation model can be represented by `V = mt + b`, where `m` is the rate of depreciation per year and `b` is the initial value.



  • Y-intercept: This occurs when `t = 0`. So, `V = m(0) + b = b`.

    In this context, `b` represents the initial purchase price of the machine. This is the value of the machine at the moment it was bought.




  • X-intercept: This occurs when `V = 0`. So, `0 = mt + b`, which means `t = -b/m`.

    In this context, `-b/m` represents the time (in years) when the machine's value depreciates completely to zero. This indicates the end of its useful life, from an accounting perspective.




Understanding these intercepts allows businesses to plan for replacement, calculate annual depreciation for tax purposes, and assess the true cost of assets over time.

JEE Relevance: While direct "real-world application" problems specific to intercepts are less common in the JEE Mathematics paper, understanding the conceptual meaning of intercepts is vital. It aids in interpreting graphs in Physics (e.g., motion graphs) and can be indirectly useful in problems involving linear functions, inequalities, or even optimization, where initial conditions or boundary limits are defined by intercepts. For CBSE, direct application problems might appear, emphasizing the practical significance.

The ability to translate a real-world scenario into a mathematical model and interpret its intercepts is a crucial skill, reinforcing the practical utility of coordinate geometry.
πŸ”„ Common Analogies

Understanding abstract mathematical concepts often becomes easier when we can relate them to familiar, real-world scenarios. Analogies serve as powerful tools for this purpose, helping to build an intuitive grasp of ideas like intercepts of a line.



Common Analogies for Intercepts of a Line


The concept of interceptsβ€”where a line 'cuts' or 'crosses' the coordinate axesβ€”can be visualized through several simple analogies:





  • The Ladder Against a Wall:

    • Imagine a ladder leaning against a vertical wall and resting on a horizontal floor.

    • The ladder represents the straight line.

    • The floor represents the X-axis.

    • The wall represents the Y-axis.

    • The point where the ladder touches the floor is the X-intercept. Notice that at this point, its height (Y-coordinate) is zero. So, it's (x, 0).

    • The point where the ladder touches the wall is the Y-intercept. At this point, its horizontal distance from the wall (X-coordinate) is zero. So, it's (0, y).

    • This analogy clearly demonstrates why one coordinate is always zero at an intercept.




  • Cutting a Cake with a Knife:

    • Consider a flat, rectangular cake (representing the coordinate plane).

    • A straight cut made by a knife through the cake represents the line.

    • The two straight edges of the cake (e.g., the front edge and the left edge) can represent the X-axis and Y-axis, respectively.

    • The point where the knife's cut meets the front edge of the cake is the X-intercept.

    • The point where the knife's cut meets the left edge of the cake is the Y-intercept.

    • Each cut is independent, just as finding the x-intercept doesn't directly give you the y-intercept, but both are points on the same line.




  • A River Crossing a Road:

    • Imagine a straight road running East-West (this is your X-axis).

    • Imagine another straight river running North-South (this is your Y-axis).

    • Now, consider a straight pipeline or a new pathway (this is your line) being constructed.

    • The point where this pathway crosses the road is the X-intercept.

    • The point where this pathway crosses the river is the Y-intercept.

    • The coordinate system provides a 'map' for these crossing points.





For both CBSE Board Exams and JEE Main, a strong visual understanding built through such analogies can significantly aid in problem-solving, especially when dealing with applications involving lines, areas, or transformations. These analogies reinforce the fundamental idea that intercepts are simply the points where a line intersects the reference axes, always having one coordinate as zero.

πŸ“‹ Prerequisites

Prerequisites for Intercepts of a Line on Coordinate Axes


To effectively understand and calculate the intercepts a line makes on the coordinate axes, a foundational understanding of several core concepts in Coordinate Geometry and Algebra is essential. This section outlines the key prerequisites.





  • Cartesian Coordinate System:


    • Concept: A system used to define the position of a point in a plane using two perpendicular axes (X-axis and Y-axis) intersecting at an origin (0,0). Each point is represented by an ordered pair (x, y), where x is the abscissa and y is the ordinate.


    • Relevance: Intercepts are points where a line crosses these specific axes. Understanding the structure and terminology of the coordinate plane is fundamental.




  • Equation of a Straight Line (Basic Forms):


    • Concept: Familiarity with different forms of linear equations, such as the general form (Ax + By + C = 0) and the slope-intercept form (y = mx + c).


    • Relevance: The problem of finding intercepts typically starts with the equation of a line. Knowing how to interpret and manipulate these equations is crucial for substituting values and solving for intercepts.




  • Understanding Coordinate Axes Properties:


    • Concept:

      • The equation of the X-axis is y = 0. Any point on the X-axis has its y-coordinate equal to zero (e.g., (5, 0), (-2, 0)).

      • The equation of the Y-axis is x = 0. Any point on the Y-axis has its x-coordinate equal to zero (e.g., (0, 3), (0, -4)).




    • Relevance: This is the most direct prerequisite. To find the x-intercept, we substitute y = 0 into the line's equation. To find the y-intercept, we substitute x = 0.




  • Solving Linear Equations in One Variable:


    • Concept: The ability to isolate a variable and find its value in a simple linear equation (e.g., solving 2x + 6 = 0 for x, or 3y - 9 = 0 for y).


    • Relevance: After substituting x = 0 or y = 0 into the line's equation, you will be left with a linear equation in one variable that needs to be solved to find the intercept value.





Mastering these foundational concepts will ensure a smooth understanding and application of techniques for finding intercepts of a line on coordinate axes, a skill frequently tested in both CBSE and JEE examinations.

⚠️ Common Exam Traps

Common Exam Traps: Intercepts of a Line on Coordinate Axes


Understanding intercepts is fundamental, but students often fall into specific traps during exams. Being aware of these common pitfalls can significantly improve accuracy and save valuable time, especially in JEE Main where precision and speed are crucial.





  • Confusing X and Y-intercepts:

    This is arguably the most frequent error. Students often swap the definitions or values. The x-intercept is the x-coordinate of the point where the line crosses the x-axis (where y = 0). The y-intercept is the y-coordinate of the point where the line crosses the y-axis (where x = 0).


    Tip: Always remember: x-intercept means 'y is zero', y-intercept means 'x is zero'. Write down the correct variable to set to zero before calculating.




  • Sign Errors:

    When calculating intercepts from an equation like Ax + By + C = 0, students sometimes mishandle signs, especially with the constant term or coefficients. For example, if the equation is 2x - 3y + 6 = 0:



    • For x-intercept (y=0): 2x + 6 = 0 implies 2x = -6 implies x = -3. (x-intercept is -3, not 3).

    • For y-intercept (x=0): -3y + 6 = 0 implies -3y = -6 implies y = 2. (y-intercept is 2, not -2).


    Tip: Double-check the sign of the constant term and coefficients when rearranging the equation to solve for the intercept.




  • Misinterpreting Intercept Form:

    The intercept form of a line is (frac{x}{a} + frac{y}{b} = 1), where 'a' is the x-intercept and 'b' is the y-intercept. A common trap is forgetting that the right-hand side must be 1. If you have (frac{x}{2} + frac{y}{3} = 5), the intercepts are NOT 2 and 3. You must divide the entire equation by 5 first: (frac{x}{10} + frac{y}{15} = 1), making the intercepts 10 and 15.


    Tip: Always convert the equation to the standard intercept form (frac{x}{a} + frac{y}{b} = 1) before identifying 'a' and 'b' as intercepts.




  • Special Cases – Lines Through the Origin:

    If a line passes through the origin (e.g., y = 2x or Ax + By = 0), both its x-intercept and y-intercept are zero. Students sometimes incorrectly assume one doesn't exist or assign arbitrary values. This is particularly relevant for JEE questions involving properties of lines passing through the origin.




  • Special Cases – Lines Parallel to Axes:

    • A line parallel to the x-axis (y = k, where k
      eq 0
      ) has a y-intercept at k, but it does not have an x-intercept (it never crosses the x-axis).

    • A line parallel to the y-axis (x = k, where k
      eq 0
      ) has an x-intercept at k, but it does not have a y-intercept (it never crosses the y-axis).


    Warning: In these cases, stating "intercept is undefined" or "does not exist" is correct, not "intercept is zero."




  • Confusing Intercept with Distance from Origin:

    The x-intercept or y-intercept can be a negative value (e.g., x-intercept = -3). However, if a question asks for the length of the segment cut off by the axes, or the distance of the intercept from the origin, it must always be positive. For instance, if the x-intercept is -3, the distance from the origin is |-3| = 3.


    Tip for JEE: Pay close attention to wording. "Intercept" can be positive or negative, "length" or "distance" must be positive.



⭐ Key Takeaways

Key Takeaways: Intercepts of a Line on Coordinate Axes



Understanding intercepts is fundamental in coordinate geometry, especially for visualizing lines and solving problems involving areas and distances. Here are the core concepts you must grasp:





  • Definition of Intercepts:


    • The x-intercept is the x-coordinate of the point where the line crosses the x-axis. At this point, the y-coordinate is always 0. To find it, set y = 0 in the line's equation.


    • The y-intercept is the y-coordinate of the point where the line crosses the y-axis. At this point, the x-coordinate is always 0. To find it, set x = 0 in the line's equation.


    Both CBSE and JEE emphasize these basic definitions and methods.




  • The Intercept Form of a Line:

    A non-vertical and non-horizontal line having x-intercept 'a' (where a ≠ 0) and y-intercept 'b' (where b ≠ 0) can be represented by the equation:






    x
    a

    +

    y
    b

    =
    1



    This form is incredibly useful for problems directly involving intercepts.




  • Deriving Intercepts from General Form (Ax + By + C = 0):

    From the general equation of a line, Ax + By + C = 0 (where C ≠ 0):




    • x-intercept = -C/A (if A ≠ 0)


    • y-intercept = -C/B (if B ≠ 0)


    If C = 0, the line passes through the origin, and both intercepts are 0.




  • Special Cases:


    • Line through Origin (C=0): If the line passes through the origin (0,0), both its x-intercept and y-intercept are 0.


    • Line Parallel to x-axis (y = k): The line has no x-intercept (unless k=0, in which case it is the x-axis) and its y-intercept is k.


    • Line Parallel to y-axis (x = k): The line has no y-intercept (unless k=0, in which case it is the y-axis) and its x-intercept is k.




  • JEE Main Application: Area of Triangle Formed by a Line and Coordinate Axes:

    A common JEE problem involves finding the area of the triangle formed by a line and the coordinate axes. If a line has x-intercept 'a' and y-intercept 'b', it forms a right-angled triangle with the origin (0,0) and the points (a,0) and (0,b).


    The area of this triangle is given by: Area = 1/2 |a × b|. Remember to use the absolute value as area must be positive.




  • Importance of Signs: The signs of 'a' and 'b' in the intercept form indicate which quadrant the intercepts lie in. For instance, if a > 0 and b > 0, the line passes through the first quadrant, whereas if a < 0 and b > 0, it passes through the second quadrant. This helps in quick visualization.



Mastering these key points will allow you to efficiently solve problems related to lines, their positions, and the regions they enclose with the coordinate axes in both board exams and JEE Main.

🧩 Problem Solving Approach

Problem Solving Approach: Intercepts of a Line on Coordinate Axes



Understanding how to efficiently find and use intercepts is crucial for solving a variety of coordinate geometry problems, especially in JEE Main. This section outlines a systematic approach.

1. Understanding the Core Concept


Before solving, always remember the definitions:

  • X-intercept: The x-coordinate of the point where the line crosses the x-axis. At this point, the y-coordinate is 0.

  • Y-intercept: The y-coordinate of the point where the line crosses the y-axis. At this point, the x-coordinate is 0.



2. Methods to Find Intercepts



There are two primary methods, each suitable for different problem types:

Method A: Using the General Form of a Line (Ax + By + C = 0)


This is the most fundamental and universally applicable method.

  1. To find the X-intercept:

    • Set y = 0 in the equation Ax + By + C = 0.

    • Solve for x: Ax + C = 0 ⇒ x = -C/A.

    • The x-intercept is -C/A. (Provided A ≠ 0)



  2. To find the Y-intercept:

    • Set x = 0 in the equation Ax + By + C = 0.

    • Solve for y: By + C = 0 ⇒ y = -C/B.

    • The y-intercept is -C/B. (Provided B ≠ 0)




JEE Tip: This method is robust even when the constant term C is zero (line passes through origin) or when the line is parallel to an axis (A=0 or B=0).



Method B: Using the Intercept Form of a Line (x/a + y/b = 1)


This form is explicitly designed to reveal intercepts.

  1. The x-intercept is 'a'.

  2. The y-intercept is 'b'.


Conversion Strategy: If you have a line in general form Ax + By + C = 0 (where C ≠ 0):


  • Move the constant term to the right side: Ax + By = -C.

  • Divide the entire equation by -C (assuming C ≠ 0): (Ax)/(-C) + (By)/(-C) = 1.

  • Rearrange to match the intercept form: x/(-C/A) + y/(-C/B) = 1.

  • Thus, the x-intercept is a = -C/A and the y-intercept is b = -C/B.



JEE Tip: This method is highly efficient when the problem directly gives intercepts or asks for the equation of a line based on its intercepts. It's also useful for quick calculations of areas of triangles formed by the line and axes (Area = 1/2 |ab|).



3. Common Problem Scenarios & Approach




























Problem Type Approach / Strategy
Finding intercepts given a line's equation (e.g., 3x + 4y = 12)

  • Use Method A (set y=0 for x-intercept, x=0 for y-intercept).

  • Alternatively, convert to intercept form (x/4 + y/3 = 1) if C ≠ 0 for quicker identification.


Finding the equation of a line given its intercepts (e.g., x-intercept = 3, y-intercept = -5)

  • Directly use the intercept form: x/a + y/b = 1. (x/3 + y/(-5) = 1).

  • Simplify to general form if required.


Line passes through a point (x1, y1) and has intercepts 'a' and 'b'. Find relation or equation.

  • Start with intercept form: x/a + y/b = 1.

  • Substitute (x1, y1) into the equation: x1/a + y1/b = 1. This gives a relation between 'a' and 'b'.

  • Additional conditions (e.g., a+b=k, ab=k) will help solve for 'a' and 'b'.


Line forms a triangle of a specific area with coordinate axes.

  • Let intercepts be 'a' and 'b'. The vertices of the triangle are (0,0), (a,0), and (0,b).

  • Area = 1/2 * base * height = 1/2 * |a| * |b|.

  • Use this relation along with other given conditions to find 'a' and 'b'.




Special Cases (CBSE & JEE):


  • If the line passes through the origin, both x and y intercepts are 0. The intercept form x/a + y/b = 1 is not applicable (a or b would be 0, leading to division by zero). In such cases, use y = mx or Ax + By = 0.

  • If the line is parallel to the x-axis (y = k), it has no x-intercept (unless k=0, then it's the x-axis itself, having infinite x-intercepts) and a y-intercept of k.

  • If the line is parallel to the y-axis (x = k), it has an x-intercept of k and no y-intercept (unless k=0, then it's the y-axis itself, having infinite y-intercepts).




Stay sharp and practice converting between forms quickly. Mastering intercepts is a foundational step for more complex coordinate geometry problems!
πŸ“ CBSE Focus Areas

CBSE Focus Areas: Intercepts of a Line on Coordinate Axes



For CBSE board examinations, understanding the intercepts a line makes on the coordinate axes is a fundamental concept. It forms the basis for several types of questions, focusing on conceptual clarity and straightforward application of formulas and derivation.



Key Concepts for CBSE Exams:


CBSE generally emphasizes the following aspects related to intercepts:



  • Definition of Intercepts:

    • The x-intercept is the x-coordinate of the point where the line crosses the x-axis. At this point, the y-coordinate is 0. If the line passes through (a, 0), then 'a' is the x-intercept.

    • The y-intercept is the y-coordinate of the point where the line crosses the y-axis. At this point, the x-coordinate is 0. If the line passes through (0, b), then 'b' is the y-intercept.



  • Intercept Form of a Line:

    This is a particularly important form for CBSE. If a line makes intercepts 'a' and 'b' on the x-axis and y-axis respectively, its equation is given by:


    $$ frac{x}{a} + frac{y}{b} = 1 $$


    You should be able to derive this form using the two-point form (points (a, 0) and (0, b)) or by other methods.



  • Finding Intercepts from Different Forms of Equations:

    • From General Form (Ax + By + C = 0):

      • To find the x-intercept, set y = 0: Ax + C = 0 ⇒ x = -C/A.

      • To find the y-intercept, set x = 0: By + C = 0 ⇒ y = -C/B.



    • From Slope-Intercept Form (y = mx + c):

      • The y-intercept is directly 'c'.

      • To find the x-intercept, set y = 0: 0 = mx + c ⇒ x = -c/m.







Typical CBSE Questions:


Expect questions that require you to:



  • Directly find intercepts: Given the equation of a line, find its x and y intercepts.

  • Form the equation: Given the intercepts, write the equation of the line using the intercept form.

  • Area of a triangle: Find the area of the triangle formed by a given line and the coordinate axes. This is a common application where the intercepts (a, 0) and (0, b) define the base and height, respectively, of a right-angled triangle. The area is (1/2) |a| |b|.

  • Geometric properties: Problems involving lines passing through a point and making specific intercepts (e.g., intercepts whose sum is fixed, or which are in a certain ratio).




"A variable line passes through (h,k) and makes intercepts on axes whose sum is 'S'. Find the locus of the centroid of the triangle formed by the line and axes."




Example for CBSE:


Question: Find the intercepts made by the line $3x - 4y = 12$ on the coordinate axes. Also, find the area of the triangle formed by this line and the coordinate axes.


Solution:



  • To find the x-intercept: Set y = 0 in the equation.

    $3x - 4(0) = 12 Rightarrow 3x = 12 Rightarrow x = 4$.

    So, the x-intercept is 4. The line passes through (4, 0).

  • To find the y-intercept: Set x = 0 in the equation.

    $3(0) - 4y = 12 Rightarrow -4y = 12 Rightarrow y = -3$.

    So, the y-intercept is -3. The line passes through (0, -3).

  • To find the area of the triangle: The triangle is formed by the points (0,0), (4,0), and (0,-3). This is a right-angled triangle with base length $|4-0| = 4$ units and height length $|-3-0| = 3$ units.

    Area = $frac{1}{2} imes ext{base} imes ext{height} = frac{1}{2} imes 4 imes 3 = 6$ square units.



Mastering these basic aspects will ensure a strong foundation for your CBSE examinations.

πŸŽ“ JEE Focus Areas

Jee Focus Areas: Intercepts of a Line on Coordinate Axes



Understanding the intercepts of a line on the coordinate axes is a fundamental concept in coordinate geometry, frequently appearing in JEE Main problems, often as a building block for more complex questions. This section focuses on the practical application and derivation of intercepts.

1. Definition of Intercepts


The points where a line crosses the X-axis and Y-axis are called its intercepts.


  • X-intercept: The x-coordinate of the point where the line intersects the X-axis. At this point, the y-coordinate is always 0.


  • Y-intercept: The y-coordinate of the point where the line intersects the Y-axis. At this point, the x-coordinate is always 0.



2. Finding Intercepts from Different Forms of a Line


It's crucial to be proficient in determining intercepts regardless of the given form of the linear equation.


























Form of Line Equation How to Find X-intercept How to Find Y-intercept

General Form:

Ax + By + C = 0

Set y = 0: Ax + C = 0

x-intercept = -C/A (if A β‰  0)

Set x = 0: By + C = 0

y-intercept = -C/B (if B β‰  0)

Intercept Form:

x/a + y/b = 1

Directly from the equation:

x-intercept = a

Directly from the equation:

y-intercept = b

Slope-Intercept Form:

y = mx + c

Set y = 0: 0 = mx + c

x-intercept = -c/m (if m β‰  0)

Directly from the equation:

y-intercept = c


3. JEE Main Applications and Focus Areas


For JEE Main, intercepts are rarely the sole focus but are crucial for solving problems involving:


  • Area of Triangle/Quadrilateral: Calculating the area of a triangle formed by a line and the coordinate axes. If the x-intercept is 'a' and y-intercept is 'b', the vertices of the triangle are (0,0), (a,0), and (0,b). The area is Β½ |a * b|.


  • Conditions on Lines: Problems might involve lines passing through a specific point and having intercepts that satisfy certain conditions (e.g., sum/product of intercepts, equidistant from origin, etc.). These often require using the intercept form (x/a + y/b = 1).


  • Family of Lines: Intercepts can be used to describe properties of a family of lines.


  • Shortest Distance/Perpendicular Distance: While not direct, understanding intercepts helps visualize the line's position, which is useful in distance calculations.




JEE vs CBSE: While CBSE focuses on basic calculation of intercepts, JEE problems often integrate intercept concepts with other topics like area calculation, locus, or geometric properties, requiring a deeper understanding and problem-solving skills, especially when dealing with variable intercepts.



4. Example Problem (JEE Type)


A line passes through the point P(2, 3) and has intercepts on the axes which are equal in magnitude but opposite in sign. Find the equation of the line.

Solution:
Let the x-intercept be 'a' and the y-intercept be '-a'.
The equation of the line in intercept form is:
x/a + y/(-a) = 1
x/a - y/a = 1
x - y = a

Since the line passes through P(2, 3), substitute these coordinates into the equation:
2 - 3 = a
a = -1

Therefore, the equation of the line is:
x - y = -1
or x - y + 1 = 0.

Mastering these core concepts about intercepts will significantly aid in tackling a wide range of coordinate geometry problems in JEE Main.
🌐 Overview
A line with x- and y-intercepts a and b has intercept form x/a + y/b = 1 (a, b β‰  0). Intercepts are points where the line meets axes: (a, 0) and (0, b). Special cases: horizontal (b = ∞), vertical (a = ∞). Relations link intercepts to slope and general form.
πŸ“š Fundamentals
β€’ Intercept form: x/a + y/b = 1.
β€’ Slope in terms of intercepts: m = βˆ’b/a (after rearrangement y = βˆ’(b/a)x + b).
β€’ General form Ax + By + C = 0 β†’ intercepts: a = βˆ’C/A (if Aβ‰ 0), b = βˆ’C/B (if Bβ‰ 0).
πŸ”¬ Deep Dive
Normal form x cosΞ± + y sinΞ± = p: relate p and Ξ± to intercepts and slope; shortest distance interpretations.
🎯 Shortcuts
β€œIntercepts insert into x/a + y/b = 1.”
πŸ’‘ Quick Tips
β€’ If A=0 or B=0 in general form, handle horizontal/vertical cases separately.
β€’ Negative intercepts indicate crossing on negative axes; plot accordingly.
🧠 Intuitive Understanding
Intercepts are the β€œfootprints” of the line on the axes. The intercept form normalizes the equation so those footprints are read directly as a and b.
🌍 Real World Applications
Budget lines (x- and y-intercepts where one good is purchased exclusively), engineering constraints, and graphics clipping to axes.
πŸ”„ Common Analogies
Two points define a line: choosing the axis crossing points makes a and b the most convenient pair of points.
πŸ“‹ Prerequisites
Coordinate axes, slope and equation of a line, solving linear equations for intercepts.
⚠️ Common Exam Traps
β€’ Dropping minus signs when converting forms.
β€’ Misreading intercepts when the line passes through negative axes.
β€’ Treating horizontal/vertical lines with the generic intercept formula.
⭐ Key Takeaways
β€’ Intercept form reads axis crossings directly.
β€’ Beware of signs when line crosses negative axes.
β€’ Convert forms to exploit whichever is most convenient.
🧩 Problem Solving Approach
Find intercepts via substitutions; write intercept form; cross-check with slope-intercept; sketch quickly to validate positions/quadrants.
πŸ“ CBSE Focus Areas
Finding intercepts; converting between forms; simple applications to graphical constraints and budget lines.
πŸŽ“ JEE Focus Areas
Distance from origin in terms of intercepts; problems involving intercepts with conditions; sign-sensitive cases across quadrants.

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Intercepts of a line on coordinate axes

Subject: Mathematics
Sub-unit: 10.1 - Basics
Complexity: Mid
Syllabus: JEE_Main

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