
Question: Find the acute angle between two lines whose slopes are $m_1 = 1/2$ and $m_2 = 3$.
Question: Find the acute angle between the lines $y = 2x + 3$ and $x + 3y = 6$.

Mastering the formulas and conditions for angles between two lines is crucial for both JEE Main and board exams. Here are some effective mnemonics and shortcuts to help you recall them quickly and accurately, especially under exam pressure.
This is the cornerstone formula for finding the angle between two lines with slopes m1 and m2.
Think: "Tan of the angle is the Difference Over One Plus the Product." The absolute value ensures you get the acute angle.
Two lines are parallel if and only if their slopes are equal.
Visualize two parallel railway tracks; they both have the 'same inclination' or slope with respect to the ground.
Two lines are perpendicular if and only if the product of their slopes is -1.
The `tan θ` formula doesn't directly apply when one or both lines are vertical (e.g., `x = k`).
Example: Find the angle between `x=3` and `y=x+1`.
The line `x=3` is vertical (makes 90° with x-axis).
The line `y=x+1` has slope `m=1`. `α = tan-1(1) = 45°`.
The angle between them is `|90° - 45°| = 45°`. This approach is much faster than trying to manipulate the formula with an undefined slope.
By effectively using these mnemonics and shortcuts, you can quickly recall the necessary conditions and formulas, saving precious time in your exams and reducing the chances of errors. Keep practicing and apply them consistently!
By keeping these quick tips in mind, you can efficiently solve problems related to angles between lines and avoid common mistakes in exams. Practice with diverse problem types to solidify your understanding.
At any intersection, two lines always form two pairs of vertically opposite angles. Consequently, there are generally two distinct angles formed between any two non-parallel, non-coincident lines: an acute angle (less than 90Β°) and an obtuse angle (greater than 90Β°). Unless specified otherwise, when we talk about the "angle between two lines," we usually refer to the acute angle.
Understanding the angle between lines is crucial for solving various geometry problems. It allows us to:
In architecture, the stability and aesthetics of a structure often depend on the angles formed by its components. Architects use angles between lines (e.g., walls, beams, roof slopes) to ensure structural integrity, optimize space, and create visually appealing designs. For example, the angle of a roof determines its ability to shed water or withstand snow loads. Similarly, the angles in a truss bridge are calculated to distribute forces efficiently.
Pilots, sailors, and land surveyors extensively use angles between lines. In navigation, the angle between a ship's current course and a lighthouse's bearing helps determine its position. Surveyors use instruments like theodolites to measure angles between sightlines to establish property boundaries, create maps, or design infrastructure projects like roads and pipelines. The concept of bearings (angles measured clockwise from North) is a direct application of angles between lines.
In robotics, controlling the movement and orientation of robot arms or autonomous vehicles requires precise angle calculations. For instance, to move an object from one point to another, a robot arm needs to calculate the angles of its joints. In computer graphics, rendering 3D objects, determining camera angles, or simulating collisions often involves calculating angles between vectors (which can be represented as lines). This helps in creating realistic animations and interactive environments.
The principles of angles between lines are vital in various branches of physics and engineering:
City planners use angles to design efficient road networks, locate public services, and plan green spaces. The grid pattern of many cities, or the radial patterns, are all based on specific angular relationships between streets and landmarks.
Understanding abstract mathematical concepts often becomes easier when we relate them to familiar objects or situations. Analogies serve as mental bridges, connecting new ideas to existing knowledge. For the topic "Angles between two lines," these analogies can provide intuitive clarity, especially when visualizing how lines intersect and what 'angle' truly represents in coordinate geometry.
These analogies are primarily for conceptual clarity and visualization. While they build intuition, remember that for solving problems in JEE Main or CBSE exams, a firm grasp of the formulas involving slopes ($ an heta = left| frac{m_1 - m_2}{1 + m_1 m_2}
ight| $) and dot products (for vectors, which can represent lines) is essential. Use these mental models to reinforce your understanding, not replace the mathematical methods.
To effectively grasp the concept of "Angles between two lines," a solid understanding of several fundamental topics in Coordinate Geometry and basic Trigonometry is essential. Revisiting these prerequisites will ensure you can confidently tackle the formulas and problem-solving techniques involved.
Here are the key prerequisites you should be familiar with:
Relevance: The entire framework of straight lines relies on this foundation.
Relevance: The formula for the angle between two lines directly uses the slopes of the lines. This is a core concept for both CBSE and JEE.
Relevance: You will often be given line equations in these forms and need to extract their slopes. Essential for JEE problem-solving speed.
Relevance: These are specific cases of angles between lines (0Β° and 90Β° respectively) and are fundamental. Expected knowledge for CBSE and JEE.
Relevance: The formula for the angle between lines uses the tan function extensively. Knowledge of common tan values and quadrant rules is vital for JEE.
Relevance: The formula for the acute angle between two lines involves an absolute value to ensure the angle obtained is acute (positive). This is used in JEE questions asking for the acute angle.
Mastering these foundational concepts will make your journey through "Angles between two lines" much smoother and more intuitive, ultimately boosting your performance in both board exams and competitive tests like JEE.
Pro Tip: Always perform a quick mental check. If lines look roughly perpendicular, expect a slope product near -1. If they seem parallel, expect slopes to be similar. This helps catch gross calculation errors.
Understanding the angle between two straight lines is a foundational concept in coordinate geometry, critical for both board exams and competitive tests like JEE Main. These key takeaways summarize the essential formulas and conditions you must remember.
If two non-vertical lines have slopes mβ and mβ, the acute angle θ between them is given by:
tan θ = |(mβ - mβ) / (1 + mβmβ)|
The absolute value ensures that θ is always the acute angle (i.e., 0 ≤ θ < π/2). To find the obtuse angle, subtract the acute angle from π (or 180Β°).
Two lines are parallel if and only if their slopes are equal.
Two lines are perpendicular if and only if the product of their slopes is -1.
The main formula tan θ = |(mβ - mβ) / (1 + mβmβ)| does not directly apply if one or both slopes are undefined (i.e., a vertical line, x = constant).
If two lines make angles αβ and αβ with the positive x-axis (their inclinations), then the angle θ between them is θ = |αβ - αβ| or θ = π - |αβ - αβ|. This method is particularly useful when dealing with vertical lines or when direct slopes are not easily calculated.
| Aspect | CBSE Board Exams | JEE Main |
|---|---|---|
| Direct Application | Primarily direct calculation of angle given two line equations or points. | Requires understanding conditions for parallel/perpendicular lines deeply, especially with variable coefficients. |
| Problem Complexity | Straightforward problems where slopes are easily found. | Often integrated into multi-concept problems (e.g., finding parameters for specific angles, properties of triangles/quadrilaterals formed by lines, concurrency). |
| Special Cases | Basic handling of vertical lines (undefined slope) as a separate case. | Expect cases where slopes can be zero or undefined, requiring careful consideration of the formula's applicability. |
Mastering these conditions and formulas is crucial as they form the backbone for solving more complex problems involving geometric figures and their properties in coordinate geometry.
Solving problems involving the angle between two lines requires a systematic approach, ensuring all cases are considered. This section outlines a step-by-step methodology to tackle such questions effectively for both JEE Main and board exams.
Before finding the angle, ensure you can extract the slope ($m$) of each line from its given equation:
$ an heta = left| frac{m_1 - m_2}{1 + m_1 m_2}
ight|$
Question: Find the acute angle between the lines $x - 2y + 3 = 0$ and $3x + y - 1 = 0$.
Solution:
Tip: Always double-check your slope calculations and be careful with signs when applying the formula. Remember to consider the special cases of vertical lines and perpendicular lines.
For CBSE board examinations, understanding the angle between two lines is a fundamental concept. The questions typically test the direct application of formulas and understanding of special conditions. Mastering these basics is crucial for scoring well in this section.
CBSE questions generally fall into these categories:
JEE vs. CBSE Focus:
While the core formulas are identical, CBSE questions for "Angles between two lines" are generally more direct and computational. JEE Advanced might delve into more complex geometric scenarios, locus problems, or involve the rotation of axes, but for JEE Main and CBSE, a solid understanding of the direct application of these formulas is key. Ensure you can confidently derive slopes and apply the angle formula correctly.
Keep practicing a variety of problems to solidify your understanding!
Understanding the angle between two lines is a fundamental concept in coordinate geometry, extensively tested in JEE Main. While the basic formula is straightforward, JEE problems often involve its application in complex scenarios, geometric properties, and finding unknown parameters.
Given two non-vertical lines with slopes $m_1$ and $m_2$, the angle $ heta$ between them is given by:
$ an heta = left| frac{m_1 - m_2}{1 + m_1 m_2}
ight|$
These conditions are frequently used to solve problems and are crucial for JEE:
JEE questions often integrate this concept with other topics. Focus on:
While CBSE focuses on direct application of the formula, JEE demands deeper conceptual understanding and the ability to apply these conditions in more abstract and multi-step problems. Expect questions involving multiple lines, geometric figures, or finding locus points based on angle conditions.
Question: Find the value of 'k' if the line $(k-3)x - (k^2-2)y + 5 = 0$ is perpendicular to the line $7x - 5y + 1 = 0$.
Solution Strategy:
This approach directly tests your understanding of slopes and the perpendicularity condition, a common JEE pattern.
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Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
Find the acute angle between lines with slopes $m_1 = 2$ and $m_2 = -3$.
| Calculation (Wrong - No Modulus) | Result |
|---|---|
| $ an heta = frac{2 - (-3)}{1 + (2)(-3)} = frac{5}{1 - 6} = -1$ | Student concludes $ heta = 135^circ$. (Obtuse, fails to answer the acute angle requirement). |
Using $m_1 = 2$ and $m_2 = -3$ for the acute angle:
| Calculation (Correct - With Modulus) | Result |
|---|---|
| $ an heta = left| frac{2 - (-3)}{1 + (2)(-3)} ight| = left| frac{5}{-5} ight| = |-1| = 1$ | $ heta = 45^circ$. (Acute angle). |
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