| Analogy for Self-Inductance | Explanation |
|---|---|
| Mass in mechanics | Just as mass resists changes in its state of motion (inertia), an inductor resists changes in the current flowing through it. It doesn't oppose current itself, but the *change* in current. |
| Real-World Example for Mutual Inductance | Explanation |
|---|---|
| Transformers | This is the most common application! A transformer works entirely on the principle of mutual induction. A changing current in the primary coil induces an EMF in the secondary coil, allowing us to step up or step down AC voltages. |
| Wireless Charging | Your wireless phone charger uses mutual induction! A coil in the charging pad creates a changing magnetic field that induces a current in a coil inside your phone, charging its battery. |
| Energy Storage Analogy | Comparison |
|---|---|
| Kinetic Energy | $KE = frac{1}{2}mv^2$. Mass (m) is analogous to inductance (L), and velocity (v) is analogous to current (I). Both represent energy stored due to motion or flow. |
| Capacitor Energy | $U_C = frac{1}{2}CV^2$. Capacitor stores energy in an electric field, inductor stores energy in a magnetic field. |
Welcome, aspiring physicists! Today, we're going to embark on a deep dive into the fascinating world of Inductance. This concept is absolutely crucial for understanding how circuits behave when currents change, and it forms the backbone of many electrical devices we use daily. We'll explore two main types: Self-Inductance and Mutual Inductance, and then delve into the idea of energy stored in an inductor. Get ready to build a robust conceptual and mathematical understanding!
Recall Faraday's Law of Electromagnetic Induction, which states that a changing magnetic flux through a coil induces an electromotive force (EMF). Mathematically, $mathcal{E} = -N frac{dPhi_B}{dt}$. Lenz's Law further clarifies the direction of this induced EMF: it always opposes the change in magnetic flux that produced it. These fundamental laws set the stage for understanding inductance.
Imagine a coil of wire. When you pass a current through it, it produces a magnetic field, and thus magnetic flux passes through its own turns. Now, what happens if this current changes? According to Faraday's law, a changing current means a changing magnetic field, which in turn means a changing magnetic flux through the coil itself. This changing flux will induce an EMF within the *same* coil. This phenomenon is called self-induction. Similarly, if this changing magnetic flux from one coil affects a *neighboring* coil, it induces an EMF in that neighbor โ this is mutual induction.
Just as mass is a measure of inertia in linear motion, resisting changes in velocity, self-inductance (L) is a measure of "electrical inertia," resisting changes in current.
Consider a coil carrying a current $I$. This current produces a magnetic field, and a magnetic flux $Phi_B$ passes through the coil's own turns. Experiments show that for a given coil, the total magnetic flux ($NPhi_B$, where $N$ is the number of turns and $Phi_B$ is the flux through one turn) linked with it is directly proportional to the current $I$ flowing through it.
Thus, we can write:
$NPhi_B propto I$
Introducing a constant of proportionality, we define Self-Inductance (L):
$NPhi_B = LI$ (Equation 1)
Where:
If the current $I$ in the coil changes with time, the magnetic flux linkage $NPhi_B$ also changes. By Faraday's Law, this changing flux linkage induces an EMF in the coil itself. Differentiating Equation 1 with respect to time:
$frac{d(NPhi_B)}{dt} = L frac{dI}{dt}$
And from Faraday's Law, the induced EMF is $mathcal{E} = -frac{d(NPhi_B)}{dt}$. Therefore, the self-induced EMF is:
$mathcal{E} = -L frac{dI}{dt}$ (Equation 2)
The negative sign is a direct consequence of Lenz's Law, indicating that the induced EMF opposes the change in current. If the current is increasing ($frac{dI}{dt} > 0$), the induced EMF opposes the current flow. If the current is decreasing ($frac{dI}{dt} < 0$), the induced EMF tries to maintain the current flow.
From $mathcal{E} = -L frac{dI}{dt}$, we can write $L = -frac{mathcal{E}}{dI/dt}$.
The SI unit of self-inductance is the Henry (H).
1 Henry = 1 Volt-second/Ampere = 1 Ohm-second.
It's a relatively large unit, so millihenrys (mH) and microhenrys ($mu$H) are often used.
The self-inductance of a coil depends solely on its geometric configuration and the magnetic properties of the material filling its core. It does not depend on the current flowing through it.
Key factors include:
Example: Self-Inductance of a Long Solenoid (JEE Advanced Focus)
Consider a long solenoid of length $l$, cross-sectional area $A$, and $N$ turns. Let $n = N/l$ be the number of turns per unit length.
When a current $I$ flows through the solenoid, the magnetic field inside it (assuming it's very long) is approximately uniform and given by:
$B = mu_0 n I = mu_0 frac{N}{l} I$ (for an air core)
The magnetic flux through each turn is $Phi_B = B A = mu_0 frac{N}{l} I A$.
The total flux linkage with the solenoid is $NPhi_B = N left( mu_0 frac{N}{l} I A
ight) = mu_0 frac{N^2 A}{l} I$.
Comparing this with $NPhi_B = LI$, we get the self-inductance:
$L = mu_0 frac{N^2 A}{l} = mu_0 n^2 A l$
If the core has a relative permeability $mu_r$, then $mu_0$ is replaced by $mu = mu_0 mu_r$.
This derivation clearly shows how L depends on the coil's geometry and the core material.
When a current is established in an inductor, work must be done against the self-induced EMF. This work is not dissipated as heat (assuming an ideal inductor with no resistance); instead, it is stored as potential energy in the magnetic field created by the inductor.
Consider an inductor with self-inductance $L$. When a current $I$ is flowing through it, and we try to increase this current by a small amount $dI$ in a time $dt$, the self-induced EMF is $mathcal{E} = -L frac{dI}{dt}$.
The power supplied by the external source to overcome this opposing EMF is $P = (-mathcal{E}) I$. (Note: We use $(-mathcal{E})$ because the external source must do positive work against the induced EMF, which opposes the current).
So, $P = left(L frac{dI}{dt}
ight) I = LI frac{dI}{dt}$.
The small amount of work $dU$ done in time $dt$ to increase the current from $I$ to $I+dI$ is $dU = P dt = LI frac{dI}{dt} dt = LI dI$.
To find the total energy $U$ stored when the current increases from $0$ to a final value $I_f$, we integrate $dU$:
$U = int_0^{I_f} LI dI = L int_0^{I_f} I dI = L left[ frac{I^2}{2}
ight]_0^{I_f}$
Therefore, the energy stored in an inductor carrying a current $I$ is:
$U = frac{1}{2}LI^2$
This energy is stored in the magnetic field established by the current.
For a long solenoid, we know $L = mu_0 n^2 A l$ and $B = mu_0 n I$, which means $I = frac{B}{mu_0 n}$.
Substituting $L$ and $I$ into the energy formula:
$U = frac{1}{2} (mu_0 n^2 A l) left( frac{B}{mu_0 n}
ight)^2$
$U = frac{1}{2} (mu_0 n^2 A l) frac{B^2}{mu_0^2 n^2}$
$U = frac{1}{2} frac{B^2}{mu_0} A l$
Since $Al$ is the volume $V$ of the solenoid where the magnetic field is concentrated, the energy density $u_B$ (energy per unit volume) is:
$u_B = frac{U}{V} = frac{B^2}{2mu_0}$
This formula for magnetic energy density is analogous to the energy density in an electric field ($u_E = frac{1}{2}epsilon_0 E^2$) and is a universal expression for any magnetic field in free space.
While self-inductance deals with a coil's response to its own changing current, mutual inductance describes how a changing current in one coil can induce an EMF in a *neighboring* coil.
Consider two coils, Coil 1 and Coil 2, placed near each other.
Let current $I_1$ flow through Coil 1. This current produces a magnetic field that extends into the region of Coil 2, resulting in some magnetic flux $Phi_{21}$ passing through Coil 2 (flux through Coil 2 due to current in Coil 1).
It is found that the flux linkage with Coil 2, due to current $I_1$ in Coil 1, is directly proportional to $I_1$:
$N_2 Phi_{21} propto I_1$
Introducing a constant of proportionality, we define the Mutual Inductance ($M_{21}$):
$N_2 Phi_{21} = M_{21} I_1$ (Equation 3a)
Similarly, if current $I_2$ flows through Coil 2, it produces a flux $Phi_{12}$ through Coil 1. We can define $M_{12}$:
$N_1 Phi_{12} = M_{12} I_2$ (Equation 3b)
It can be mathematically proven (and is a very important result) that $M_{12} = M_{21} = M$. This means the mutual inductance between two coils is a symmetric property, regardless of which coil is considered the primary.
If the current $I_1$ in Coil 1 changes with time, the flux $Phi_{21}$ through Coil 2 also changes, inducing an EMF in Coil 2. From Faraday's Law and Equation 3a:
$mathcal{E}_2 = -N_2 frac{dPhi_{21}}{dt} = -frac{d}{dt}(M I_1)$
Assuming $M$ is constant (depends only on geometry):
$mathcal{E}_2 = -M frac{dI_1}{dt}$ (Equation 4a)
Similarly, if current $I_2$ in Coil 2 changes, it induces an EMF in Coil 1:
$mathcal{E}_1 = -M frac{dI_2}{dt}$ (Equation 4b)
Like self-inductance, the SI unit of mutual inductance is the Henry (H).
Mutual inductance depends on:
The extent to which two coils are magnetically coupled is quantified by the coefficient of coupling (k). It is defined such that:
$M = k sqrt{L_1 L_2}$
Where:
The value of $k$ ranges from 0 to 1:
Example: Mutual Inductance of Two Coaxial Solenoids (JEE Advanced)
Consider two long coaxial solenoids.
The total flux linkage with Coil 2 is $N_2 Phi_{21} = N_2 left( mu_0 frac{N_1}{l} I_1 (pi r_1^2)
ight)$.
Comparing with $N_2 Phi_{21} = M I_1$, we get the mutual inductance:
$M = mu_0 frac{N_1 N_2 pi r_1^2}{l}$
Notice that M depends only on the geometry of both coils. If the current were in the outer solenoid ($I_2$), the field $B_2$ would be $mu_0 frac{N_2}{l} I_2$. The flux linkage with the inner solenoid would be $N_1 (B_2 A_1)$. Calculating this also yields the same M, verifying $M_{12} = M_{21}$.
If two inductors $L_1$ and $L_2$ are connected in series and there is no mutual inductance between them, the total induced EMF across the combination is the sum of individual induced EMFs:
$mathcal{E}_{eq} = mathcal{E}_1 + mathcal{E}_2$
$mathcal{E}_{eq} = -L_1 frac{dI}{dt} - L_2 frac{dI}{dt}$
$mathcal{E}_{eq} = -(L_1 + L_2) frac{dI}{dt}$
Comparing with $mathcal{E}_{eq} = -L_{eq} frac{dI}{dt}$, we get:
$L_{eq} = L_1 + L_2$ (For series, no mutual inductance)
For inductors in parallel, the voltage across them is the same, and the total current is the sum of individual currents:
$mathcal{E} = -L_1 frac{dI_1}{dt} = -L_2 frac{dI_2}{dt}$
$I = I_1 + I_2 implies frac{dI}{dt} = frac{dI_1}{dt} + frac{dI_2}{dt}$
From the voltage equation, $frac{dI_1}{dt} = -frac{mathcal{E}}{L_1}$ and $frac{dI_2}{dt} = -frac{mathcal{E}}{L_2}$.
Substituting into the current derivative equation:
$frac{dI}{dt} = -frac{mathcal{E}}{L_1} - frac{mathcal{E}}{L_2} = -mathcal{E} left( frac{1}{L_1} + frac{1}{L_2}
ight)$
Since $frac{dI}{dt} = -frac{mathcal{E}}{L_{eq}}$:
$frac{1}{L_{eq}} = frac{1}{L_1} + frac{1}{L_2}$ (For parallel, no mutual inductance)
This is a trickier but important JEE concept. When mutual inductance is present, the induced EMF in each coil is affected by the changing current in the *other* coil, as well as its own changing current.
There are two cases for series connection with mutual inductance:
$mathcal{E}_1 = -L_1 frac{dI}{dt} - M frac{dI}{dt}$ (Induced EMF in L1 due to its own current + due to current in L2, where $I_1=I_2=I$)
$mathcal{E}_2 = -L_2 frac{dI}{dt} - M frac{dI}{dt}$
Total EMF: $mathcal{E}_{eq} = mathcal{E}_1 + mathcal{E}_2 = -(L_1+L_2+2M) frac{dI}{dt}$
$L_{eq} = L_1 + L_2 + 2M$
$mathcal{E}_1 = -L_1 frac{dI}{dt} + M frac{dI}{dt}$ (The mutual induced EMF opposes the self-induced EMF)
$mathcal{E}_2 = -L_2 frac{dI}{dt} + M frac{dI}{dt}$
Total EMF: $mathcal{E}_{eq} = mathcal{E}_1 + mathcal{E}_2 = -(L_1+L_2-2M) frac{dI}{dt}$
$L_{eq} = L_1 + L_2 - 2M$
The actual configuration (aiding or opposing) depends on how the coils are connected relative to each other's winding direction. Dot notation is often used in circuit diagrams to indicate the relative phasing of the windings for mutual inductance.
| Aspect | CBSE (Board Exams) | JEE Main & Advanced |
|---|---|---|
| Definitions | Clear definitions of self-inductance (L) and mutual inductance (M), their units, and the induced EMF formulas. | In-depth understanding of definitions, physical intuition, and precise mathematical formulation. |
| Derivations | Derivation of $mathcal{E} = -L frac{dI}{dt}$ and $U = frac{1}{2}LI^2$. Qualitative factors affecting L & M. | Derivation of L for a solenoid, M for coaxial solenoids. Derivation of energy density $u_B = frac{B^2}{2mu_0}$. |
| Calculations | Direct application of formulas to calculate L, M, induced EMF, or stored energy given values. | Complex problems involving multiple inductors, variable currents, finding instantaneous EMF/current, energy loss/gain scenarios. Calculation of L, M, and energy density for various geometries. |
| Concepts | Basic understanding of Lenz's Law application. Inductors as energy storage devices. | Deep conceptual understanding of magnetic coupling, coefficient of coupling (k), series/parallel combinations of inductors *with* mutual inductance, RL circuits (transient analysis often involves inductors heavily). |
| Problem Solving | Relatively straightforward plug-and-play problems. | Multi-concept problems, often requiring integration or differential equations, and a strong grasp of vector calculus for flux calculations in advanced cases. |
Understanding inductance is pivotal. It helps us design transformers, chokes, filters, and many other essential components in electrical and electronic circuits. Keep practicing with diverse problems to solidify your grasp!
Welcome to the 'Mnemonics and Short-Cuts' section for Self and Mutual Inductance! This section provides clever memory aids and quick conceptual links to help you master these important topics for JEE and board exams.
Leveraging analogies can significantly simplify remembering complex formulas and their structures.
| Concept | Mechanical Analogue | Magnetic/Electric Analogue | Key Analogy Point |
|---|---|---|---|
| Kinetic Energy | $KE = frac{1}{2} m v^2$ | Energy in Inductor: $U_L = frac{1}{2} L I^2$ | Mass (m) $leftrightarrow$ Inductance (L) Velocity (v) $leftrightarrow$ Current (I) This similarity makes remembering $U_L$ much easier. |
| Electric Field Energy Density | - | $u_E = frac{1}{2} epsilon_0 E^2$ | Magnetic Field Energy Density: $u_B = frac{B^2}{2mu_0}$ (or $frac{1}{2mu_0} B^2$) Notice the similar structure. Permittivity ($epsilon_0$) is in the numerator for electric, while Permeability ($mu_0$) is in the denominator for magnetic. |
By using these mnemonics and short-cuts, you can quickly recall formulas and concepts, saving valuable time during exams and reducing the chances of error. Practice applying them with various problems!
JEE Tip: While derivations are important, conceptual clarity on *why* these phenomena occur and *what* they represent will significantly aid in solving complex problems, especially those involving energy conservation in LC circuits or transient behavior.
| Mechanical System | Electromagnetic System |
|---|---|
| Mass ($m$) | Inductance ($L$) |
| Velocity ($v$) | Current ($I$) |
| Kinetic Energy ($frac{1}{2}mv^2$) | Stored Energy ($frac{1}{2}LI^2$) |
To effectively grasp the concepts of self-inductance, mutual inductance, and energy stored in an inductor, a strong foundation in the following topics is essential. These concepts form the bedrock upon which the complexities of electromagnetic induction in circuits are built.
Mastering these foundational topics will make your journey through self and mutual inductance significantly smoother and more intuitive.
Navigating the concepts of self and mutual inductance and energy in inductors requires precision, as several subtle points can lead to common exam traps. Be mindful of these pitfalls to secure full marks.
By being mindful of these common traps, you can approach problems on self and mutual inductance with greater accuracy and confidence.
Mastering these core concepts and formulas is fundamental for tackling problems on electromagnetic induction. Practice applying them to various circuit scenarios.
Solving problems related to self and mutual inductance, and energy storage in inductors requires a systematic approach, often involving careful application of definitions and circuit principles. This section outlines key strategies for tackling such problems in JEE Main.
By following these systematic steps and understanding the nuances of each formula, you can effectively solve problems on self and mutual inductance and energy stored in inductors.
For the CBSE Board Examinations, the topics of Self and Mutual Inductance, along with the energy stored in an inductor, are fundamentally important. Emphasis is primarily on clear definitions, underlying principles, derivations, and direct application of formulas in numerical problems. Conceptual understanding of the factors affecting inductance is also crucial.
Motivational Tip: Mastering these derivations and formulas will fetch you easy marks in the board exams. Focus on understanding the steps, not just memorizing the final result!
Welcome to the 'JEE Focus Areas' for Self & Mutual Inductance and Energy in Inductors! This topic is crucial for JEE Main, often appearing in both direct formula-based questions and more conceptual circuit problems. A strong grasp of these concepts is essential for scoring well.
These are particularly important for JEE Main and require understanding transient behavior.
Mastering these areas will significantly boost your score in Electromagnetic Induction. Practice problems involving various circuit configurations and calculations of L and M.
No CBSE problems available yet.
No JEE problems available yet.
No videos available yet.
No images available yet.
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
| Case | Sign of M | Energy Formula | Calculation (for opposing case above) |
|---|---|---|---|
| Series Aiding | +M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 + M I^2$ | $2 + 2 + 2 = 6 ext{ J}$ |
| Series Opposing | -M | $U = frac{1}{2} L_1 I^2 + frac{1}{2} L_2 I^2 - M I^2$ | $2 + 2 - 2 = 4 ext{ J}$ (Correct) |
No summary available yet.
No educational resource available yet.