| Complex Number (z) | Real Part (a = Re(z)) | Imaginary Part (b = Im(z)) |
|---|---|---|
| $z_1 = 3 + 4i$ | $3$ | $4$ |
| $z_2 = -2 + 5i$ | $-2$ | $5$ |
| $z_3 = 7 - i$ | $7$ | $-1$ (since $-i$ is $-1 imes i$) |
| $z_4 = sqrt{2} + frac{1}{3}i$ | $sqrt{2}$ | $frac{1}{3}$ |
| $z_5 = 5$ | $5$ | $0$ (This can be written as $5 + 0i$) |
| $z_6 = -6i$ | $0$ (This can be written as $0 - 6i$) | $-6$ |
Intuition Builder:
Imagine you're giving directions. "Go 3 blocks East, then 2 blocks North." This tells you your final position relative to a starting point. In the complex plane, "3" is like going "East" (along the real axis) and "2i" is like going "North" (along the imaginary axis). The complex number $3+2i$ tells you exactly where you end up!
Visual Representation (Imagine this as a standard XY plane, but X is Real Axis and Y is Imaginary Axis):
^ Imaginary Axis (Im(z))
|
z2(-2,4) .
| . z1(3,2)
|
<----(-4,0)---+---(0,0)----+---(3,0)-----> Real Axis (Re(z))
| O z5
|
. z6(0,-2)
|
z3(-4,-3) .
. z4(5,-1)
| Concept | Description | Key Formula/Property |
|---|---|---|
| Algebraic Form ($a+ib$) | Standard way to write a complex number. 'a' is real part, 'b' is imaginary part. Both 'a' and 'b' are real numbers. | $z = a+ib$, $Re(z)=a$, $Im(z)=b$ |
| Equality | Two complex numbers are equal if their real and imaginary parts are individually equal. | $a_1+ib_1 = a_2+ib_2 iff a_1=a_2 ext{ and } b_1=b_2$ |
| Argand Diagram | Geometric representation of complex numbers as points $(a,b)$ or position vectors in a 2D plane (Complex Plane). | Real Axis (horizontal), Imaginary Axis (vertical) |
| Modulus | Distance of the complex number $z=a+ib$ from the origin $(0,0)$ in the Argand plane. Always non-negative. | $|z| = sqrt{a^2+b^2}$ |
| Distance Between Two Points | The distance between $z_1$ and $z_2$ in the Argand plane. Crucial for locus problems. | $|z_1-z_2| = sqrt{(a_1-a_2)^2 + (b_1-b_2)^2}$ |
| Quadrant | `a` & `b` Signs | Mnemonic Part | `arg(z)` (Principal) |
|---|---|---|---|
| Q1 | `a > 0, b > 0` | As Is | `alpha` |
| Q2 | `a < 0, b > 0` | Pi Minus | `π - alpha` |
| Q3 | `a < 0, b < 0` | Minus Pi | `alpha - π` |
| Q4 | `a > 0, b < 0` | Negative Alpha | `-alpha` |
Mastering the representation of complex numbers and their visualization on the Argand plane is fundamental. These quick tips will help you solidify your understanding and tackle related problems efficiently.
z = a + ib:a is the real part (Re(z)) and b is the imaginary part (Im(z)). Both a and b are real numbers. Common Mistake: Im(z) is b, not ib.z = a + ib is uniquely defined by the ordered pair (a, b).z = a + ib, simply plot the point (a, b) on this plane. The origin (0,0) corresponds to the complex number 0 + 0i.z = a + 0i means point (a, 0)).z = 0 + bi means point (0, b)).|z|) - Geometric Interpretation:|z| = |a + ib| = √(a² + b²) represents the distance of the point (a, b) from the origin (0,0) on the Argand plane.z.|z - z0| = r geometrically represent a circle centered at z0 with radius r.arg(z)) - Geometric Interpretation:z is the angle θ made by the line segment connecting the origin to (a, b) with the positive real axis, measured in the counter-clockwise direction.(-π, π] or [0, 2π). Ensure you know which convention your problem/syllabus follows. JEE typically uses (-π, π].θ, first find the reference angle α = tan-1(|b/a|). Then adjust α based on the quadrant of (a, b):θ = αθ = π - αθ = -(π - α) or π + α (depending on range)θ = -α or 2π - α (depending on range)ī) and Negative (-z) on Argand Plane:ī = a - ib: This is the reflection of z across the real axis. If z = (a, b), then ī = (a, -b).-z = -a - ib: This is the reflection of z about the origin. If z = (a, b), then -z = (-a, -b).⭐ JEE Advantage: Visualizing complex numbers on the Argand plane is not just plotting; it's a powerful problem-solving tool. Many problems involving locus, inequalities, and geometric properties of complex numbers become much simpler with a clear Argand diagram visualization.
JEE Tip: Developing a strong intuitive understanding of the Argand diagram is paramount for JEE. Many problems involving loci, rotations, transformations, and inequalities can be solved much more efficiently by visualizing them geometrically on the complex plane rather than purely algebraically. Always try to sketch a complex number or its operation.
Example:
To plot `z₁ = 3 + 2i` and `z₂ = -1 + 4i` on an Argand diagram:
This simple act of plotting immediately gives a spatial context to these otherwise abstract numbers.
While complex numbers might initially seem abstract, their ability to represent both magnitude and direction/phase makes them indispensable in various real-world applications, especially in fields involving oscillations, waves, and rotations. The Argand diagram provides a crucial visual tool for understanding these applications.
The ability of complex numbers to encode two pieces of information (magnitude and phase/direction) into a single entity, coupled with the geometric insight provided by the Argand diagram, makes them an indispensable tool across numerous scientific and engineering disciplines.
JEE Tip: Recognizing this direct correspondence allows you to use your geometric intuition from coordinate geometry to solve problems involving complex numbers, especially those related to distance, locus, and transformations.
By ensuring a firm grasp of these foundational concepts, students will find the transition to understanding and manipulating complex numbers much smoother, setting a strong base for advanced topics in the unit.
JEE/CBSE Tip: For JEE, speed and accuracy in these basic identifications are paramount, as complex expressions are often part of larger problems. For CBSE, clear, neat plotting and accurate identification of 'a' and 'b' are essential for full marks on definition-based questions.
Stay vigilant and practice these fundamental steps to build a strong foundation in complex numbers!
Understanding the standard form of a complex number and its geometric interpretation on the Argand plane is fundamental for all subsequent operations and concepts in complex numbers. This foundation is critical for both CBSE Board Exams and JEE Main & Advanced.
Mastering these foundational concepts will greatly simplify your understanding of complex number operations and their geometric interpretations in solving problems, especially in JEE. Keep practicing plotting points and calculating moduli/conjugates!
Mastering the representation of complex numbers in the a + ib form and visualizing them on the Argand diagram is fundamental to solving a wide array of problems in complex numbers. A strategic approach helps in efficiently tackling both algebraic and geometric questions.
z = a + ib FormWhen dealing with expressions in the a + ib form, the primary goal is often to simplify them to this standard format or extract information from it.
z = (Real Part) + i(Imaginary Part). This is crucial for comparing complex numbers, finding real/imaginary parts, modulus, argument, etc.i: Simplify (i^n) using the cycle (i, -1, -i, 1) (powers (1, 2, 3, 4) respectively). For example, (i^{4k} = 1), (i^{4k+1} = i).The Argand diagram (or complex plane) provides a geometric interpretation. It's especially powerful for problems involving loci, distances, angles, and transformations.
| Aspect | CBSE Board Exam | JEE Main Exam |
|---|---|---|
| a + ib Form | Focus on basic operations (addition, subtraction, multiplication, division) and simplifying to a + ib. Finding real/imaginary parts. | Requires fluency in all operations, often embedded within more complex problems (e.g., quadratic equations with complex roots, series involving complex numbers). |
| Argand Diagram | Primarily for plotting points and basic geometric interpretation of modulus and argument. | Extensive use for locus problems, geometric properties of complex numbers (collinearity, concyclicity), transformations, and understanding inequalities. |
“Every complex problem has a solution, and often, an elegant one. Start by simplifying, then visualize!”
Q: Express `(3 + 2i) / (2 - i)` in the form `a + ib` and plot it on the Argand plane.
Solution Strategy:
CBSE Tip: Mastering the conversion to `a + ib` form is crucial as it's a prerequisite for almost all subsequent complex number topics like finding modulus, argument, and powers. Ensure your calculations are neat and accurate.
For JEE Main, a strong grasp of the representation of complex numbers in the form z = a + ib and their visualization on the Argand diagram is absolutely crucial. These foundational concepts are not just about defining complex numbers but are extensively used in solving problems related to geometry, locus, and algebraic manipulation. Mastering these areas will significantly aid in tackling more advanced topics like De Moivre's Theorem, roots of unity, and geometric properties of complex numbers.
Here are the key areas you must master for JEE Main:
a + ib:| Aspect | CBSE Board Exams | JEE Main |
|---|---|---|
Representation a + ib | Focus on basic algebraic operations, finding modulus and argument. | Requires mastery of complex algebraic manipulation, including rationalization and properties of conjugates and modulus. |
| Argand Diagram | Plotting points, basic geometric interpretation of |z| and arg(z). | Extensive application in locus problems, geometric properties (e.g., collinearity, concurrency), transformations, and complex geometry theorems. |
A deep conceptual understanding of these fundamental representations will be a strong asset for solving a wide array of problems in complex numbers and beyond.
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z = a + ib. Students might also confuse the imaginary unit 'i' with a variable. z = a + ib, it is uniquely represented by the point (a, b) in the Argand plane.z = 3 - 2i.(-2, 3) by mistakenly assigning the imaginary part to the real axis and vice-versa.-2i directly on the y-axis, rather than just -2.z = 3 - 2i:a = 3 and the imaginary part b = -2.(3, -2).(3, -2) accurately represents 3 - 2i.1+i, -2+3i, -4-i, 5-2i) to solidify the concept.z = a + ib by directly applying tan⁻¹(b/a), without accounting for the specific quadrant in which the complex number resides on the Argand plane. This leads to an incorrect angle, particularly for numbers not in the first quadrant. tan⁻¹(|b/a|) provides) with the actual principal argument. A weak grasp of coordinate geometry's quadrant rules for angles also contributes. θ, where -π < θ ≤ π):z = a + ib on the Argand diagram to identify its quadrant.α = tan⁻¹(|b/a|). This α is always an acute angle between 0 and π/2.θ = αθ = π - αθ = α - π (or -(π - α))θ = -αz = -1 - i:Arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4. This is incorrect as z is in the 3rd quadrant.z = -1 - i:a = -1 and b = -1. The complex number lies in the third quadrant.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.z is in the third quadrant, the principal argument θ = α - π = π/4 - π = -3π/4.tan⁻¹ function typically returns values in (-π/2, π/2), which needs manual adjustment for other quadrants.1. Modulus: For `z = 3 - 4i`, students might incorrectly write `|z| = √(3² - (-4)²) = √(9 - 16) = √(-7)` (incorrect, as `b²` must be positive).
2. Argument: For `z = -1 + i`, directly calculating `Arg(z) = tan⁻¹(1/-1) = tan⁻¹(-1) = -π/4` (incorrect, as `z` is in Q2).
1. Modulus: For `z = 3 - 4i`, `a=3, b=-4`.
`|z| = √(3² + (-4)²) = √(9 + 16) = √25 = 5`.
2. Argument: For `z = -1 + i`, `a=-1, b=1`. This number lies in the second quadrant.
Reference angle `α = tan⁻¹(|1/-1|) = tan⁻¹(1) = π/4`.
Since `z` is in Q2, `Arg(z) = π - α = π - π/4 = 3π/4`.
reiθ) which implicitly or explicitly require radians, without proper conversion. π radians = 180°).arctan(b/a)) for argument calculation. If an angle is given in degrees, convert it to radians before using it in any complex number formula or representation. z = 1 + i. A student might incorrectly state its argument as 45°, and then try to write its exponential form as √2 * ei45. This is wrong because the exponent 'iθ' requires θ to be in radians. Similarly, using cos(45) and sin(45) from a calculator set to degrees, but then applying De Moivre's theorem where 'nθ' is expected in radians.z = 1 + i, the magnitude is |z| = √(1² + 1²) = √2. The principal argument is θ = tan⁻¹(1/1) = π/4 radians (or 45°). The correct polar form is √2(cos(π/4) + i sin(π/4)) and the correct exponential form is √2 * eiπ/4. Always ensure consistency in units.θradians = θdegrees * (π/180).z = a + ib, especially when a or b are negative. This directly impacts the complex number's polar representation and its position on the Argand diagram. The error typically arises from incorrectly identifying the quadrant or applying the tan⁻¹ function without considering the signs of a and b. arg(z) = tan⁻¹(b/a) without understanding its limitations for different quadrants.(-π, π].z = a + ib as a point (a, b) on the Argand plane. This immediately tells you its quadrant.α = tan⁻¹(|b/a|). This angle is always positive and acute.α to find the principal argument:arg(z) = αarg(z) = π - αarg(z) = -(π - α) or α - πarg(z) = -α(-π, π]. This is crucial for JEE Main problems. z = -1 - i:arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4. This is wrong because z = -1 - i lies in the third quadrant.z = -1 - i:(-1, -1) is in the third quadrant.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.-(π - α), we get arg(z) = -(π - π/4) = -3π/4. (Alternatively, α - π = π/4 - π = -3π/4).(-π, π].z = a + ib, or by incorrectly labeling the axes. This leads to the complex number being represented in the wrong quadrant or at an incorrect position on the Argand plane. While seemingly minor, this can lead to fundamental errors in further geometric interpretations or calculations of arguments. z = a + ib as a point (b, a) instead of (a, b), similar to how one might mistakenly swap x and y coordinates in standard Cartesian geometry.z = a + ib, it is precisely represented by the point P(a, b) on the Argand diagram. The horizontal axis is always the Real axis (Re(z)), and the vertical axis is always the Imaginary axis (Im(z)). The real part 'a' determines the position along the horizontal axis, and the imaginary part 'b' determines the position along the vertical axis. z = 3 - 2i, a student might incorrectly plot it as:(-2, 3) by swapping the coordinates.(3, -2) but with the horizontal axis labeled as 'Imaginary' and vertical as 'Real'.z = 3 - 2i, the correct representation on the Argand diagram is the point P(3, -2). Here, 3 is located on the positive Real axis, and -2 is located on the negative Imaginary axis. This correctly places the point in the fourth quadrant, reflecting the positive real and negative imaginary parts.z = a + ib directly to the ordered pair (a, b). Think of 'a' (real part) as the 'x-coordinate' and 'b' (imaginary part) as the 'y-coordinate'.z = a + ib, 'a' is the exact x-coordinate (Real axis) and 'b' is the exact y-coordinate (Imaginary axis).z = a + ib or determining its argument. This often leads to misidentifying the quadrant for the point (a, b), resulting in an incorrect principal argument calculated by directly using tan⁻¹(|b/a|) without proper quadrant adjustment. a (real part) and b (imaginary part) corresponding to different Argand plane quadrants.α = tan⁻¹(|b/a|) without considering the actual quadrant.a) and imaginary part (b) from z = a + ib.P(a, b) on the Argand plane to confirm its correct quadrant.α = tan⁻¹(|b/a|). This α is always positive and less than π/2.Arg(z) = αArg(z) = π - αArg(z) = -(π - α) (for principal argument in (-π, π])Arg(z) = -α (for principal argument in (-π, π])z = -1 - i.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4 and incorrectly states Arg(z) = π/4.z = -1 - i is in the third quadrant, whereas π/4 is a first-quadrant angle.z = -1 - i:a = -1 and imaginary part b = -1. The point (-1, -1) lies in the third quadrant.α = tan⁻¹(|b/a|) = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.Arg(z) = -(π - α) = -(π - π/4) = -3π/4.(a, b) on the Argand plane to visualize and confirm the correct quadrant.α = tan⁻¹(|b/a|). Second, adjust α based on the quadrant to get the actual argument. Do not skip this adjustment.z = r(cosθ + i sinθ) or z = reiθ). This 'unit conversion' error leads to incorrect values or representations. eiθ, inherently expect θ to be in radians.θ is expressed in radians when used in the polar form z = r(cosθ + i sinθ) or the Euler form z = reiθ. If you determine the angle in degrees, convert it to radians before substituting it into these forms. The conversion factor is π radians = 180°. z = 1 + i to be 45°. They then incorrectly represent its Euler form as z = √2ei45. Here, 45 is treated as radians, which is incorrect, as 45 radians is a very different angle from 45 degrees.z = 1 + i:r = |z| = √(12 + 12) = √2.Arg(z) = tan-1(1/1) = 45°.45° = 45 * (π/180) = π/4 radians.z = √2(cos(π/4) + i sin(π/4)).z = √2eiπ/4.θ is in radians unless explicitly stated otherwise for a specific context.tan-1), make sure to convert it to radians (degrees * π/180) before using it in mathematical formulas.θ = tan⁻¹(b/a) to find the argument of a complex number z = a + ib without considering the quadrant in which the complex number lies on the Argand diagram. This leads to an incorrect angle, especially for complex numbers in the second, third, or fourth quadrants. tan⁻¹ function's range, which typically outputs values between -π/2 and π/2. Students often rote-learn the formula without grasping the geometric interpretation on the Argand plane or the necessity of quadrant analysis to find the correct principal argument θ ∈ (-π, π]. θ of a complex number z = a + ib, always follow these steps:(a, b) on the Argand diagram to determine its quadrant.α = tan⁻¹(|b/a|). This angle α is always between 0 and π/2.θ = αθ = π - αθ = -(π - α) or θ = α - π (within (-π, π])θ = -αz = -1 + i√3:θ = tan⁻¹(√3 / -1) = tan⁻¹(-√3) = -π/3. This is incorrect.z = -1 + i√3:a = -1 (negative), b = √3 (positive). This is in Quadrant II.α = tan⁻¹(|√3 / -1|) = tan⁻¹(√3) = π/3.θ = π - α = π - π/3 = 2π/3.α = tan⁻¹(|b/a|), then adjust it.θ lies in the interval (-π, π].a) and the imaginary part (b) of a complex number z = a + ib, particularly when the terms are not arranged in the standard order or involve negative signs. This error directly impacts the correct plotting on the Argand diagram and subsequent calculations like modulus or argument. a + ib form. Sometimes, students confuse the coefficient of i with the real part or vice-versa, especially when the real term is absent or appears after the imaginary term. z = a + ib before extracting the values of a and b. The real part (a) is the term that does not contain i, and the imaginary part (b) is the coefficient of i. z = 4i - 7.a = 4 and b = -7. This would lead to plotting the point (4, -7) on the Argand diagram.z = 4i - 7:z = -7 + 4i.a = -7 and b = 4.a + ib.a (real part), and the coefficient of 'i' is b (imaginary part).a and b.z = x + iy by incorrectly identifying the quadrant on the Argand diagram or applying the wrong formula for that quadrant. This leads to an incorrect sign or value for the angle. tan-1(y/x) without adjusting for the correct quadrant, or confusing the formulas for π - α, α - π, or -α where α = tan-1(|y/x|).(x, y) corresponding to z = x + iy on the Argand diagram to identify its exact quadrant.α = tan-1(|y/x|). This α is always positive and lies in (0, π/2).Arg(z) (lying in (-π, π]):Arg(z) = αArg(z) = π - αArg(z) = α - π (or -(π - α))Arg(z) = -αz = -1 + i. A common mistake is to calculate α = tan-1(|1/-1|) = tan-1(1) = π/4 and then incorrectly assume Arg(z) = π/4.z = -1 + i:(-1, 1) lies in the Second Quadrant.α = tan-1(|1/-1|) = tan-1(1) = π/4.z is in the Second Quadrant, Arg(z) = π - α = π - π/4 = 3π/4.Arg(z) in each quadrant.Arg(z) value lies within the principal argument range (-π, π].tan⁻¹(|b/a|) directly to find the argument of a complex number z = a + ib, without considering the quadrant in which the complex number lies on the Argand plane. This leads to an incorrect principal argument (angle). α = tan⁻¹(|b/a|) gives only the reference angle (acute angle with the positive x-axis) and not the principal argument directly for all quadrants. Lack of visualization on the Argand diagram is a major contributing factor. z = a + ib on the Argand diagram to identify its quadrant. First, calculate the reference angle α = tan⁻¹(|b/a|). Then, adjust α according to the quadrant to find the principal argument (θ), which must lie in the range (-π, π]. z = -1 + i, a common mistake is to calculate arg(z) = tan⁻¹(|1/-1|) = tan⁻¹(1) = π/4. This is incorrect because z = -1 + i lies in the second quadrant.z = -1 + i:a = -1, b = 1, so it's in the second quadrant.α = tan⁻¹(|1/-1|) = tan⁻¹(1) = π/4.arg(z) = π - α = π - π/4 = 3π/4. This is within the principal argument range (-π, π].θ = αθ = π - αθ = α - π (or - (π - α))θ = -αa + ib form, leading to errors in determining the correct coordinates. a + ib where a and b are purely real. z = a + ib form, where a and b are real numbers, before identifying its real part (a) and imaginary part (b) for plotting on the Argand diagram. The complex number z is then represented by the point (Re(z), Im(z)) on the Argand plane.z = (2 + i) / (1 - i). A student might incorrectly assume Re(z) = 2 and Im(z) = 1 or similar values from the numerator, or struggle to identify real/imaginary parts directly without simplification.z = (2 + i) / (1 - i) on the Argand diagram:a + ib form:z = (2 + i) / (1 - i) * (1 + i) / (1 + i)z = (2 + 2i + i + i^2) / (1^2 - i^2)z = (2 + 3i - 1) / (1 + 1)z = (1 + 3i) / 2z = 1/2 + (3/2)iRe(z) = 1/2 and Im(z) = 3/2.z is represented by the point (1/2, 3/2).a + ib form.a' and 'b' you identify are indeed real numbers, free from any i terms or other complex components.z = a + ib as ib instead of correctly recognizing it as just b. This misunderstanding often leads to errors in plotting complex numbers on the Argand diagram, including incorrect coordinates or swapping the Real and Imaginary axes. a + ib form. The 'i' is part of the unit for the imaginary component, but the imaginary part itself is the coefficient of 'i'. Students also tend to rush, overlooking the fundamental mapping of (a, b) to the Argand plane's coordinates. z = a + ib:Re(z), is a.Im(z), is b (a real number, the coefficient of i).z = a + ib is plotted as the point (a, b). z = 5 - 2i:Re(z) = 5Im(z) = -2i(5, -2i) or incorrectly swap axes and plot (-2, 5).z = 5 - 2i:Re(z) = 5Im(z) = -2z is represented by the point (5, -2) on the Argand diagram, which lies in the fourth quadrant.Im(z) is a real number—it's the coefficient of i.-3 - 4i means (-3, -4), not (3, 4). These fundamental errors can lead to incorrect answers in complex locus problems or vector addition/subtraction.z = a + ib on the Argand plane, which leads to incorrect calculation of its principal argument (angle). This often stems from overlooking the signs of the real part (a) and the imaginary part (b). a and b are always positive when using formulas.arctan(|b/a|) without considering the quadrant where the point (a, b) lies.a and b: Clearly state the real part a and imaginary part b, including their signs.(a, b) on the Argand diagram. This immediately tells you the quadrant.α = tan⁻¹(|b/a|). This angle is always positive and acute.θ (typically in (-π, π]):θ = αθ = π - αθ = -(π - α) or θ = π + α (use the former for principal argument)θ = -αz = -1 - i:arg(z) = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4. This is incorrect because z is in the 3rd quadrant.z = -1 - i:a = -1 and b = -1.(-1, -1) lies in the 3rd Quadrant.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.θ = -(π - α).θ = -(π - π/4) = -3π/4.z = -1 - i.a and b.(-π, π].Students frequently calculate the principal argument (Arg(z)) of a complex number z = a + ib by simply finding tan⁻¹(b/a). This leads to errors because the tan⁻¹ function typically returns an angle in (-π/2, π/2), failing to account for the actual quadrant of the complex number on the Argand diagram.
tan⁻¹(|b/a|) to find a reference angle but forget to adjust it based on the signs of a and b.(-π, π] (or [0, 2π) depending on convention, though (-π, π] is standard for JEE).To correctly find the principal argument Arg(z) of z = a + ib:
Plot on Argand Diagram: Always sketch the complex number z = (a, b) on the Argand plane to determine its quadrant.
Calculate Reference Angle: Find the reference angle α = tan⁻¹(|b/a|). This α will always be in [0, π/2).
Adjust for Quadrant:
Arg(z) = αArg(z) = π - αArg(z) = -(π - α) or α - πArg(z) = -αJEE Tip: For numbers on axes:
z = a (a>0): Arg(z) = 0z = a (a<0): Arg(z) = πz = ib (b>0): Arg(z) = π/2z = ib (b<0): Arg(z) = -π/2Consider z = -1 - i.
Wrong: Arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4.
This is incorrect because π/4 is in the 1st quadrant, while -1 - i is clearly in the 3rd quadrant.
Consider z = -1 - i.
Correct:
1. Plot z = (-1, -1) on the Argand diagram. It lies in the 3rd Quadrant.
2. Calculate the reference angle: α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.
3. Adjust for the 3rd Quadrant: Arg(z) = -(π - α) = -(π - π/4) = -3π/4.
(-π, π].θ = tan⁻¹(y/x) directly to find the argument of a complex number z = x + iy without considering the specific quadrant in which the complex number lies on the Argand plane. This oversight leads to an incorrect value for the argument. tan⁻¹ function (or arctan) typically returns an angle in the range (-π/2, π/2) or (-90°, 90°), which is only correct for Quadrant I and IV (and sometimes Quadrant II and III if `x` is positive by mistake).Arg(z) of a complex number z = x + iy (where Arg(z) ∈ (-π, π]):(x, y) representing z to identify its quadrant.α = tan⁻¹(|y/x|). This angle will always be between 0 and π/2.Arg(z) = αArg(z) = π - αArg(z) = -(π - α) or α - πArg(z) = -αz = x (real and positive), Arg(z) = 0z = -x (real and negative), Arg(z) = πz = iy (purely imaginary, y > 0), Arg(z) = π/2z = -iy (purely imaginary, y < 0), Arg(z) = -π/2z = -1 - i, calculating Arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4.z = -1 - i:(-1, -1) lies in Quadrant III on the Argand plane.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.z is in Quadrant III, the correct principal argument is Arg(z) = -(π - α) = -(π - π/4) = -3π/4.Arg(z) is conventionally defined in the interval (-π, π].θ = tan⁻¹(b/a) without considering the specific quadrant in which the complex number lies on the Argand plane. This leads to an incorrect angle, particularly for complex numbers in the 2nd, 3rd, or 4th quadrants, where the direct `tan⁻¹` value might only give the reference angle. (-π, π] (or (-180°, 180°]).z = -1 - i√3.z = -1 - i√3.tan⁻¹(|b/a|) without understanding that it only gives the reference angle, not the actual argument in the specific quadrant.α = tan⁻¹(|b/a|), where α is always in [0, π/2]. Then, adjust α based on the identified quadrant to find the principal argument (θ) in the range (-π, π].Arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4. This is incorrect because z = -1 - i lies in the third quadrant, and π/4 is an angle in the first quadrant.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.θ = - (π - α) = - (π - π/4) = -3π/4.| Quadrant | Condition | Principal Argument (θ) |
|---|---|---|
| I | a > 0, b > 0 | α |
| II | a < 0, b > 0 | π - α |
| III | a < 0, b < 0 | α - π (or -(π - α)) |
| IV | a > 0, b < 0 | -α |
tan⁻¹(b/a) as the argument for all quadrants. Instead, use tan⁻¹(|b/a|) to find the reference angle and then adjust it based on the quadrant.(-π, π]. Angles outside this range need to be adjusted (e.g., by adding or subtracting 2π).a + ib form. This fundamental error, usually due to insufficient simplification, leads to incorrect calculations of both the modulus |z| = sqrt(a^2 + b^2) and the argument arg(z). a + ib form. Common culprits include neglecting to rationalize denominators or incorrectly grouping real and imaginary terms. a + ib form first. This is crucial for accurate calculations.z = a + ib form, calculate the modulus: |z| = sqrt(a^2 + b^2).alpha = tan-1(|b/a|). Then, use the quadrant of (a, b) on the Argand plane to determine the principal argument (e.g., Q1: alpha, Q2: pi-alpha, Q3: alpha-pi, Q4: -alpha).z = 1 / (1 + i), a common error is to assume a=1, b=1 directly from the denominator. This leads to incorrect modulus |z| = sqrt(2) or argument arg(z) = pi/4 for 'z'.z = 1 / (1 + i):z = (1 / (1 + i)) * ((1 - i) / (1 - i)) = (1 - i) / 2 = 1/2 - (1/2)i.a = 1/2 and b = -1/2.|z| = sqrt((1/2)^2 + (-1/2)^2) = sqrt(1/4 + 1/4) = sqrt(1/2) = 1/sqrt(2).a > 0 and b < 0, z lies in the 4th quadrant. The reference angle alpha = tan-1(|-1/2 / 1/2|) = tan-1(1) = pi/4. Therefore, the principal argument arg(z) = -alpha = -pi/4.a + ib form before applying modulus or argument formulas. This is a crucial first step for complex expressions.(a, b) on the Argand plane to ensure the principal value (within (-pi, pi]) is found.Students frequently interchange the real and imaginary parts when plotting a complex number z = a + ib on the Argand diagram. This leads to plotting the point (b, a) instead of the correct (a, b). Additionally, misinterpretation of the signs of a and b can lead to incorrectly placing the point in the wrong quadrant.
This common mistake stems from a lack of clarity regarding the assignment of the real and imaginary parts to the respective axes. Students might mistakenly treat the complex number like an ordered pair (x, y) from general coordinate geometry without consistently associating x with the real part and y with the imaginary part. Overlooking the signs of a and b also contributes to quadrant errors.
When representing a complex number z = a + ib on an Argand diagram, it is crucial to remember the following:
Re(z) = a).Im(z) = b).Therefore, the complex number z = a + ib is plotted as the point P(a, b) on the Argand plane. Always identify the real part (a) and the imaginary part (b) correctly, including their signs, before plotting.
Incorrectly plotting z = -2 + 3i as the point (3, -2) on the Argand plane (associating 3 with the real axis and -2 with the imaginary axis, or swapping coordinates).
To correctly plot z = -2 + 3i:
a = -2.b = 3.(-2, 3), which lies in the second quadrant.a) with the X-axis and the Imaginary part (b) with the Y-axis. Think (Re(z), Im(z)).a and b. For example, for z = -3 - 2i, a = -3 and b = -2 (third quadrant).z = 5) and pure imaginary (e.g., z = -4i) numbers.z = a + ib on the Argand plane. This primarily involves incorrectly identifying the signs of the real part (a) or the imaginary part (b), leading to the complex number being plotted in the wrong quadrant. For instance, -2 + 3i might mistakenly be plotted in the first quadrant instead of the second, impacting geometric interpretation and subsequent calculations. a and b as direct Cartesian coordinates without proper attention to the signs.a and b with specific Argand plane quadrants.z = a + ib on the Argand diagram:a) and imaginary part (b).z = a + ib corresponds to the point (a, b) on the Argand plane (Real axis = x, Imaginary axis = y).a and b to place the point in the correct quadrant:a > 0, b > 0a < 0, b > 0a < 0, b < 0a > 0, b < 0Complex Number: z = -3 + 2i
Wrong Plotting: Student incorrectly identifies a = 3 (ignoring the negative sign) and b = 2, plotting the point (3, 2) in Quadrant I.
Complex Number: z = -3 + 2i
Correct Approach:
a = -3 (negative)b = 2 (positive)Since a < 0 and b > 0, the complex number z lies in Quadrant II. The correct point to plot is (-3, 2) on the Argand plane.
a and b with their correct signs before plotting.a and b.This is incorrect, as `e^(i45)` (where 45 is radians, approximately 2578°) is vastly different from `e^(iπ/4)`.
tan(α) = |b/a| to find the argument (θ) without correctly adjusting the reference angle (α) based on the quadrant in which the complex number z = a + ib lies on the Argand plane. This leads to an incorrect value for θ, which is crucial for polar representation and other complex number operations. tan(α) = |b/a| only provides the reference angle (acute angle with the positive real axis).To correctly find the principal argument θ (such that -π < θ ≤ π) for z = a + ib:
a and b, determine which quadrant the complex number z lies in on the Argand plane.α = tan⁻¹(|b/a|), where α is always an acute angle (0 < α < π/2).| Quadrant | Signs of (a, b) | Principal Argument (θ) |
|---|---|---|
| I | (+, +) | θ = α |
| II | (-, +) | θ = π - α |
| III | (-, -) | θ = α - π (or -( π - α)) |
| IV | (+, -) | θ = -α |
Consider z = -1 - i√3.
Incorrect Approach: Calculating the argument as tan⁻¹(|-√3/-1|) = tan⁻¹(√3) = π/3 and concluding that the argument is π/3. This is wrong because z is in the third quadrant.
For z = -1 - i√3:
a = -1 and b = -√3. Both are negative, so z lies in Quadrant III.α = tan⁻¹(|-√3/-1|) = tan⁻¹(√3) = π/3.z is in Quadrant III, θ = α - π = π/3 - π = -2π/3. -2π/3.To correctly find the principal argument (θ) of z = a + ib:
| Quadrant | Condition | Principal Argument (θ) |
|---|---|---|
| I | a > 0, b > 0 | θ = α |
| II | a < 0, b > 0 | θ = π - α |
| III | a < 0, b < 0 | θ = -(π - α) or α - π |
| IV | a > 0, b < 0 | θ = -α |
For z = -1 - i (which is in the 3rd quadrant):
Wrongly calculating Arg(z) as tan-1(-1/-1) = tan-1(1) = π/4.
For z = -1 - i:
z = a + ib on the Argand plane. Students might incorrectly place the real part 'a' on the vertical axis and the imaginary part 'b' on the horizontal axis, or vice-versa, leading to a wrong representation of the complex number's position. z = a + ib is correctly plotted as the point (a, b), where 'a' is the coordinate on the Real axis and 'b' is the coordinate on the Imaginary axis. This aligns with the conventional plotting of (x, y) points where x is horizontal and y is vertical. z = 3 + 2i, a student might mark 3 units on the Imaginary axis and 2 units on the Real axis, or confuse the quadrants, plotting (2, 3) instead of (3, 2).z = 3 + 2i:(3, 2) in the first quadrant accurately represents z = 3 + 2i.z = a + ib as a point (a, b), where 'a' is the x-coordinate (Real) and 'b' is the y-coordinate (Imaginary).2-4i, -3+i, -1-2i) to solidify your understanding of how signs affect position.| Quadrant | Condition | Principal Argument (θ) |
|---|---|---|
| I | a > 0, b > 0 | α |
| II | a < 0, b > 0 | π - α |
| III | a < 0, b < 0 | α - π (or -(π - α)) |
| IV | a > 0, b < 0 | -α |
a) and the imaginary part (b) of a complex number z = a + ib, especially when the number is not presented in the standard form or involves negative signs. This fundamental calculation error leads to incorrect plotting on the Argand diagram, and propagates to erroneous calculations of modulus, argument, or other complex number properties. a + ib format.-i as having an imaginary part of 1 instead of -1.i - 2 and incorrectly identifying a = 1, b = -2 instead of a = -2, b = 1.b must always be positive.z = a + ib. Clearly identify a as the term without i (the real part) and b as the coefficient of i (the imaginary part), ensuring to include their respective signs. These correct values of a and b are then used for plotting as the point (a, b) on the Argand diagram or for any subsequent calculations. z = 4 - 2i.a = 4 and b = 2 (ignoring the negative sign).(4, 2) and an incorrect argument calculation (assuming it's in the first quadrant).z = 4 - 2i.a + ib, we correctly identify a = 4 and b = -2.z is represented by the point (4, -2), which lies in the fourth quadrant.|z| = √(a² + b²) = √(4² + (-2)²) = √(16 + 4) = √20.arg(z) = tan&supmn;¹(|-2/4|) = tan&supmn;¹(1/2), and since z is in the fourth quadrant, arg(z) = -α or 2π - α where α = tan&supmn;¹(1/2).a + ib before any other operation. For example, rewrite -3i + 5 as 5 - 3i.i. If it's -i, then b = -1. If it's just i, then b = 1.a is the term *without* i, and the imaginary part b is the *coefficient* of i.a or b are zero, negative, or presented out of standard order to build accuracy.For CBSE Class 12th and JEE Main/Advanced, the following approach is crucial:
Consider converting the complex number z = 1 + i to polar form:
Magnitude: |z| = √(1² + 1²) = √2
Argument (Incorrect):
tan θ = (1/1) = 1
Mistakenly concluding θ = 45° and then (if one were to use it in Euler's formula) writing √2 e^(i45). This is incorrect as '45' in e^(i45) would be interpreted as 45 radians, not 45 degrees, leading to a completely different complex number.
Converting the complex number z = 1 + i to polar form:
Magnitude: |z| = √(1² + 1²) = √2
Argument (Correct):
tan θ = (1/1) = 1
Since z lies in the first quadrant, θ = π/4 radians.
Correct Polar Form: √2 (cos(π/4) + i sin(π/4))
Correct Exponential Form: √2 e^(iπ/4)
z = a + ib when plotting it, or making sign errors. Students might plot (b, a) instead of (a, b), or mistakenly plot (-a, b) instead of (a, -b), leading to an incorrect representation of the complex number's position in the Argand plane. z = 2 - 3i or z = -4 + i, further contributes to this error. It's often due to rushing or not firmly establishing the correspondence between a + ib and (a, b). z = a + ib, its representation on the Argand diagram is the point P(a, b).JEE Main Tip: Pay meticulous attention to the signs of both 'a' and 'b' to correctly identify the quadrant or axis where the point lies.
z = -3 + 2i, a common mistake is to plot it as (2, -3) (swapping and sign error) or (3, 2) (sign error). These points lie in different quadrants (4th and 1st respectively) than the correct one.z = -3 + 2i:a = -3b = 2P(-3, 2). This point correctly lies in the second quadrant, where x-coordinates are negative and y-coordinates are positive.Re(z) with the x-coordinate and Im(z) with the y-coordinate.z = 5, which is 5 + 0i, so (5, 0)) or purely imaginary numbers (e.g., z = -4i, which is 0 - 4i, so (0, -4)), ensure they lie on the correct axis.To correctly find the principal argument of z = a + ib:
Consider z = -1 - i. Here, a = -1, b = -1.
Incorrect approach: Student calculates arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4.
This is incorrect as the point (-1, -1) lies in Quadrant III, but π/4 corresponds to Quadrant I.
For z = -1 - i, a = -1, b = -1.
1. Plotting (-1, -1) on the Argand diagram shows it's in Quadrant III.
2. Calculate the reference angle: α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.
3. Since it's in Quadrant III, the principal argument arg(z) = -(π - α) = -(π - π/4) = -3π/4.
(Alternatively, α - π = π/4 - π = -3π/4).
tan⁻¹(b/a) without considering the signs of a and b or the specific quadrant, leading to an incorrect angle. z = a + ib on the Argand diagram.θ = tan⁻¹(b/a) directly, which only gives an angle in the first or fourth quadrant (principal value for tan⁻¹ usually in (-π/2, π/2)), without adjusting for the actual quadrant of z.(-π, π].z = a + ib on the Argand plane to identify its quadrant.α = tan⁻¹(|b/a|). This α is always positive and lies in (0, π/2).α to find the argument arg(z) based on the quadrant (for principal argument in (-π, π]):arg(z) = αarg(z) = π - αarg(z) = -(π - α) or α - πarg(z) = -αz = -1 - i.arg(z) = tan⁻¹((-1)/(-1)) = tan⁻¹(1) = π/4.z = -1 - i is in the third quadrant, not the first.z = -1 - i.a = -1 and b = -1, so z is in the third quadrant.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.z is in the third quadrant, the principal argument is -(π - α) = -(π - π/4) = -3π/4.α = tan⁻¹(|b/a|) first, then apply the quadrant rule.(-π, π] is standard, some problems might specify [0, 2π). Ensure your answer matches the required range.a + ib) to its polar form (r(cosθ + isinθ) or reiθ) is the incorrect determination of the argument (angle θ). They often calculate the reference angle using α = tan-1(|b/a|) but fail to adjust θ based on the actual quadrant of the complex number on the Argand plane. This leads to an incorrect 'unit' (angle) in the polar representation. tan-1(b/a): Students often use calculators or direct formulas without understanding that tan-1(x) typically returns an angle in the range (-π/2, π/2), which covers only the first and fourth quadrants.a and b: The signs of the real (a) and imaginary (b) parts are crucial for determining the correct quadrant, but they are often overlooked when taking the absolute ratio |b/a|.-π < θ ≤ π):z = a + ib on the Argand plane to identify the quadrant it lies in.α = tan-1(|b/a|). This angle is always positive and less than π/2.θ = αθ = π - αθ = -π + α (or π + α if using [0, 2π))θ = -α (or 2π - α if using [0, 2π))z = -1 + i√3 (JEE Advanced often involves such values):θ = tan-1(√3 / -1) = tan-1(-√3) = -π/3. Thus, they might write z = 2(cos(-π/3) + isin(-π/3)).z = -1 + i√3:a = -1 (negative real), b = √3 (positive imaginary). This complex number lies in the Second Quadrant.α = tan-1(|√3 / -1|) = tan-1(√3) = π/3.θ = π - α = π - π/3 = 2π/3.z = 2(cos(2π/3) + isin(2π/3)). Here, the modulus r = √((-1)2 + (√3)2) = √(1+3) = 2.(-π, π] for principal argument, or [0, 2π)).To correctly find the principal argument:
Consider z = -1 + i√3.
Wrong Approach: A student might calculate α = tan⁻¹(√3/1) = π/3 and incorrectly state arg(z) = π/3. This is incorrect because z lies in the second quadrant.
Consider z = -1 + i√3.
Thus, the correct principal argument is 2π/3.
Students frequently calculate the argument of a complex number z = a + ib as simply tan⁻¹(b/a). This is a critical conceptual error because it fails to account for the specific quadrant in which the complex number lies on the Argand plane, leading to an incorrect principal argument.
This mistake arises from treating tan⁻¹(b/a) as the principal argument directly, without understanding that it only provides the reference angle (α), which is always acute (between 0 and π/2). The actual principal argument (Arg(z)) must lie within the standard interval (-π, π] and is quadrant-dependent.
To correctly find the principal argument of z = a + ib:
Consider z = -1 - i.
Incorrect Calculation: Arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4.
This is wrong because z is in the third quadrant, but π/4 corresponds to the first quadrant.
For z = -1 - i:
Here, a = -1 and b = -1. Both are negative, placing z in the Quadrant III.
The reference angle α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.
Using the rule for Quadrant III, Arg(z) = α - π = π/4 - π = -3π/4.
z = x + iy as simply tan⁻¹(y/x) without considering the specific quadrant in which the complex number lies on the Argand plane. This leads to an incorrect principal argument, which is fundamental for many complex number operations. tan⁻¹ function, which typically yields a value in the range (-π/2, π/2). Students fail to realize that the argument, which is the angle from the positive real axis, must be adjusted based on the signs of x and y to correctly fall within the principal argument range of (-π, π]. z = x + iy. Use the reference angle α = tan⁻¹(|y/x|) (always an acute angle) and adjust it according to the quadrant:Arg(z) = αArg(z) = π - αArg(z) = -(π - α) (or π + α if the range is [0, 2π), but for principal argument, use -(π - α))Arg(z) = -α(-π, π]. z = -1 - i.Arg(z) = tan⁻¹(-1/-1) = tan⁻¹(1) = π/4.z = -1 - i lies in the third quadrant, but π/4 is an angle in the first quadrant.z = -1 - i:x = -1 and y = -1, which means the complex number lies in the third quadrant.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.(-π, π]:Arg(z) = -(π - α) = -(π - π/4) = -3π/4.-3π/4.(-π, π] for JEE problems.| Quadrant | Condition | arg(z) (for (-π, π]) |
|---|---|---|
| 1st | a > 0, b > 0 | α |
| 2nd | a < 0, b > 0 | π - α |
| 3rd | a < 0, b < 0 | -(π - α) or π + α |
| 4th | a > 0, b < 0 | -α or 2π - α |
(-π, π].Z = a + ib as a point (a, b) on the Argand plane. Determine its exact quadrant first. Then:α = tan⁻¹(|b/a|) (always positive).θ = αθ = π - αθ = -(π - α) or θ = α - πθ = -α(-π, π].Z = -1 - i. A common sign error for its principal argument is to calculate:arg(Z) = tan⁻¹(|-1|/|-1|) = tan⁻¹(1) = π/4Z = -1 - i:(-1, -1), which lies in the third quadrant.α = tan⁻¹(|-1/-1|) = tan⁻¹(1) = π/4.arg(Z) = -(π - α) = -(π - π/4) = -3π/4.a + ib or calculating the argument, explicitly identify the quadrant.(-π, π] range for the principal argument.No summary available yet.
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